A tetherball is a type of vertical pendulum where the ball swings freely in a horizontal circle around the pole to which it is tied (see figure). Assume the cord is frictionless where it attaches to the pole and ignore air resistance. If the ball has a mass of 0.26 kg and is moving in a circle with a radius of 1.3 m and a speed of 8.2 m/s, what is the size of the centripetal force?

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### Understanding Centripetal Force in Circular Motion

A tetherball is a type of vertical pendulum where the ball swings freely in a horizontal circle around the pole to which it is tied (see figure). Assume the cord is frictionless where it attaches to the pole and ignore air resistance. If the ball has a mass of 0.26 kg and is moving in a circle with a radius of 1.3 m and a speed of 8.2 m/s, what is the size of the centripetal force?

**Figure Explanation:**
The diagram depicts a tetherball tied to a vertical pole. The ball is shown moving in a circular path around the pole. The circular path is indicated by a dashed line, showing the radius of the circle, which is 1.3 meters.

#### Calculation of Centripetal Force

To determine the centripetal force, we use the formula:

\[ F_c = \frac{mv^2}{r} \]

where:
- \( F_c \) is the centripetal force
- \( m \) is the mass of the ball (0.26 kg)
- \( v \) is the velocity of the ball (8.2 m/s)
- \( r \) is the radius of the circle (1.3 m)

Plugging in the values:

\[ F_c = \frac{0.26 \times (8.2)^2}{1.3} \]
\[ F_c = \frac{0.26 \times 67.24}{1.3} \]
\[ F_c = \frac{17.4824}{1.3} \]
\[ F_c \approx 13.45 \, \text{N} \]

Therefore, the centripetal force is approximately 13 N.

### Multiple Choice Options:
- 0.054 N
- 1.6 N
- 51.7 N
- **13 N** (Correct Answer)

This explanation breaks down the problem, applies the relevant physics formula, and arrives at the correct answer.
Transcribed Image Text:### Understanding Centripetal Force in Circular Motion A tetherball is a type of vertical pendulum where the ball swings freely in a horizontal circle around the pole to which it is tied (see figure). Assume the cord is frictionless where it attaches to the pole and ignore air resistance. If the ball has a mass of 0.26 kg and is moving in a circle with a radius of 1.3 m and a speed of 8.2 m/s, what is the size of the centripetal force? **Figure Explanation:** The diagram depicts a tetherball tied to a vertical pole. The ball is shown moving in a circular path around the pole. The circular path is indicated by a dashed line, showing the radius of the circle, which is 1.3 meters. #### Calculation of Centripetal Force To determine the centripetal force, we use the formula: \[ F_c = \frac{mv^2}{r} \] where: - \( F_c \) is the centripetal force - \( m \) is the mass of the ball (0.26 kg) - \( v \) is the velocity of the ball (8.2 m/s) - \( r \) is the radius of the circle (1.3 m) Plugging in the values: \[ F_c = \frac{0.26 \times (8.2)^2}{1.3} \] \[ F_c = \frac{0.26 \times 67.24}{1.3} \] \[ F_c = \frac{17.4824}{1.3} \] \[ F_c \approx 13.45 \, \text{N} \] Therefore, the centripetal force is approximately 13 N. ### Multiple Choice Options: - 0.054 N - 1.6 N - 51.7 N - **13 N** (Correct Answer) This explanation breaks down the problem, applies the relevant physics formula, and arrives at the correct answer.
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