A certain indicator, HA, has a Ka value of 0.00040. The protonated form of the indicator is blue and the ionized form is red. What is the pK, of the indicator? pKa %D Incorrect

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### Determining the \( pK_a \) of an Indicator

A certain indicator, HA, has a \( K_a \) value of 0.00040. The protonated form of the indicator is blue, and the ionized form is red.

**Question:**
What is the \( pK_a \) of the indicator?

**Calculation:**
\( pK_a = \) 

(An input box is provided for the answer)

**Feedback:**
Incorrect

--- 

**Explanation:**

To find the \( pK_a \) of the indicator, use the following formula:

\[ pK_a = -\log(K_a) \]

Where:
- \( K_a \) is the acid dissociation constant.
- \( \log \) represents the logarithm base 10.

Given the \( K_a \) value:
\[ K_a = 0.00040 \]
\[ pK_a = -\log(0.00040) \]

Calculate this value to determine the \( pK_a \).

Note: Ensure your answer is correct and matches the expected value for accurate feedback.
Transcribed Image Text:### Determining the \( pK_a \) of an Indicator A certain indicator, HA, has a \( K_a \) value of 0.00040. The protonated form of the indicator is blue, and the ionized form is red. **Question:** What is the \( pK_a \) of the indicator? **Calculation:** \( pK_a = \) (An input box is provided for the answer) **Feedback:** Incorrect --- **Explanation:** To find the \( pK_a \) of the indicator, use the following formula: \[ pK_a = -\log(K_a) \] Where: - \( K_a \) is the acid dissociation constant. - \( \log \) represents the logarithm base 10. Given the \( K_a \) value: \[ K_a = 0.00040 \] \[ pK_a = -\log(0.00040) \] Calculate this value to determine the \( pK_a \). Note: Ensure your answer is correct and matches the expected value for accurate feedback.
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