The image contains a statistical problem set regarding a survey of 2009 American adults, in which 29% said they believed in astrology. The exercise is structured into two parts:**(a)** Participants are asked to calculate a confidence interval at the 99% confidence level for the proportion of all adult Americans who believe in astrology. The answers need to be rounded to three decimal places. There is a space to input the lower and upper bounds of the confidence interval, represented as two blank fields within parentheses.Below this calculation, there are multiple-choice options to interpret the resulting interval:1. We are 99% confident that this interval contains the true population mean.2. We are 99% confident that this interval does not contain the true population mean.3. We are 99% confident that the true population mean lies below this interval.4. We are 99% confident that the true population mean lies above this interval.Option 1 is marked as the correct interpretation.**(b)** This section asks for the sample size required for the width of a 99% confidence interval (CI) to be at most 0.05, regardless of the value of the sample proportion ($ \hat{p} $). The result provided is 2121.593, and there is an indication that this answer is incorrect, marked by a red cross.This exercise helps learners practice calculating and interpreting confidence intervals and understanding the relationship between sample size and interval width.

The formula for the confidence interval for the proportion is,

Answered: A certain forum reported that in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.) X * Enter a number.
In a survey of 2343 adults, 700 say they believe in UFOs. Construct a 90%confidence interval for the population proportion of adults who believe in UFOs. Part 1 A 90% confidence interval for the population proportion is ( __, __ ) Interpret your results. Choose the correct answer below. A. The endpoints of the given confidence interval shows that 90% of adults believe in UFOs. B. With 90% confidence, it can be said that the population proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. C. With 90% confidence, it can be said that the sample proportion of adults who believe in UFOs is between the endpoints of the given confidence interval. D. With 90% probability, the population proportion of adults who do not believe in UFOs is between the endpoints of the given confidence interval.
Suppose you find that the 95% confidence interval for the cost of a wedding is ($29,000, $35,000). What is the correct interpretation of this interval? Group of answer choices For the next wedding you attend, the cost will be between $29,000 and $35,000. There is a 95% probability that the sample mean is between $29,000 and $35,000. There is a 95% probability that the population mean is between $29,000 and $35,000. You are 95% confident that the mean wedding cost is between $29,000 and $35,000. thanks
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 427 randomly selected caterpillars observed, 45 lived to become butterflies. a. Use 3 decimal places to complete the following statement: With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 427 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
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Construct an 80 % confidence interval for the mean height of sons whose fathers are 70 inches tall. Round your answer to at least three decimal places. An 80 % confidence interval for the mean height of sons whose fathers are 70 inches tall is (this is part 2 of 2 of the math problem, please and thank you
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According to a poll, 79% of California adults (398 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.) Additional Materials Reading
You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 418 randomly selected caterpillars observed, 59 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 418 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
Section b is where I am struggling

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