In a random sample of 1771 Americans aged 12 to 19, 19.5% had some hearing loss.  The standard error for this sample proportion is 0.0095. Audiologists want to determine what proportion of Americans aged 12 to 19 have some hearing loss, and want to determine a 99% confidence interval for the true proportion.   What is this 99% confidence interval?         0.185 to 0.205     0.193 to 0.197     0.156 to 0.235     0.171 to 0.219

Q: Suppose​ that​ 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: we have given that sample size =n=2307 ,sample proportion =p^=18%=0.18

Q: In a survey of 3312 adults, 1447 say they have started paying bills online in the last year.…

A:

Q: You may need to use the appropriate appendix table technology to answer this question. A 95%…

A: Assume that μ is the population mean.

Q: f the following statements is true e confidence interval for a on proportion? onfidence interval for…

A: We know that  Sample proportion p^=x/n  Margin of error =E

Q: For the same sample proportion and sample size, what happens to the width of a confidence interval…

A: Solution-: For the same sample proportion and sample size, what happens to the width of a confidence…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: If n=380 and X = 304, construct a 90% confidence interval. Give your answers to three decimals…

A: Given,n=380 ,x=304p^=xnp^=304380=0.81-p^=1-0.8=0.2α=1-0.90=0.1α2=0.05Z0.05=1.645     (from Z-table)

Q: We would like to know: "What percentage of college students drink alcohol every day?" In a random…

A: Given that, N=500 X=75

Q: ool graduates, and ask them their annual incomes. They give you an average income of $35,000 per…

A: As the population standard deviation is known, we will use z distribution. The value of z at 95%…

Q: If n = 370 and p=0.31p, construct a 90% confidence interval. This should be rounded to three decimal…

A:

Q: Kim wants to determine a 80 % confidence interval for the true proportion ? of high school students…

A:

Q: A history teacher records the SAT scores of all 87 of her students. The data is used to construct a…

A: For calculating the confidence interval, we need to satisfy the following conditions: Independence…

Q: If n-19, ž(x-bar)-43, and s-8, construct a confidence interval at a 90% confidence level. Assume the…

A: Given: n = 19, x¯ = 43, s = 8 Confidence level = 90%

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: In a sample of 200 individuals, 115 indicated they are Catholic. Develop a 95% confidence interval…

A:

Q: If α = 0.05, then what is the confidence level?

A: Given: α = 0.05   we know that, Confidence level+ α = 1

Q: If n=12, x=47, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…

A: According to the provided information,

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: We have given that,  Let p̂ represents the sample proportion and E represents the margin of error,…

Q: If n = 18, = 46, and s = 16, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: Thelma and Louise are each attempting to estimate the proportion of adults who enjoy listening to…

A: Given that.  p=0.29 C.I for Thelma's=(0.242 , 0.338) C.I for Louise's=(0.237 , 0.323)

Q: Which of the following confidence intervals would have a wider width for the same set of data? A 90%…

A: We have to find which of the following confidence intervals would have a wider width for the same…

Q: A 95% confidence interval is constructed in order to estimate the proportion of all adults who are…

A: We have given a 95% confidence interval to estimate the proportion of all left-handed…

Q: A recent study of 25 students showed that they spend an average of $18.53 for gas per week. The…

A: Given: Sample size n = 25 Sample mean X = 18.53 Sample standard deviation s = 3

Q: Out of 187187 randomly selected adults in the United States who were surveyed, 7171 exercise on a…

A: A sample of 187 randomly selected adults were surveyed of which 71 exercise on a regular basis.

Q: If the alpha level is .05, then the confidence level is ?

A: Given: alpha = 0.05 confidence level / significant level = 1 - alpha

Q: /hat is the 95% confidence interval for this sample mean? to 82.0 to 67.4 to 82.9 to 67.6

A: As the population standard deviation is known, we will use z distribution. The critical value z at…

Q: Suppose a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at or below the…

A: In question, Given that a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at…

Q: f n=19, sample mean=50, and s =8, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

A:

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: Suppose that 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: The sample proportion is given as 0.18. The sample size is given as 2307. The two-tailed z-critical…

Q: To construct a 95% Confidence Interval, we have to find the margin of error (ME), and we can use the…

A: From the provided information, Confidence level = 95% Standard error (SE) = 0.049 The z value at 95%…

Q: a sample of 25 automobiles shows that the mean price was $20,500 with standard deviation of $2,500.…

A: Givensample size = n = 25Mean price = $20,500Standard deviation = $2500 The distribution is normal.…

Q: Suppose the standard deviation of the losses had been $3600 instead of $1800. What would the larger…

A:

Q: If n = 220, p-hat = 0.4, then what will be the 90% Confidence Interval for the population…

A:

Q: Use the Student's t distribution to

A: From the given information, the confidence level is 0.95 Significance level is 1-0.95=0.05 Given…

Q: A 95% confidence interval for a proportion is (0.62, 0.88). From this we can infer: O The population…

A: We have to find out confident interval for a proportion ...

Q: A confidence interval for a population proportion p is 0.635 to 0.700. What is the margin of error?

A: We have given that confidence interval for a population proportion p is 0.635 to 0.700.

Q: If we find a 95% confidence interval using a sample, then we can say... 95% of individuals will fall…

A: Given that:A 95% confidence interval using a sample is obtained.To find:The interpretation of this…

Q: If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95%…

A: The formula for a confidence interval for the population mean μ\mu when the population standard…

Q: Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she…

A: From the provided information, The data values are as follow: 9, 12, 13, 10 and 10 Sample size (n) =…

Q: We wish to estimate what percent of adult residents in Pierce County have a high school degree. Out…

A: The sample proportion is, p^=xn=361405=0.8914 Computation of critical value:…