A dlinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 16 subjects had a mean wake time of 105.0 min. After treatment, the 16 subjects had a mean wake time of 99.5 min and a standarddeviation of 20.3 min. Assume that the 16 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest aboutthe mean wake time of 105.0 min before the treatment? Does the drug appear to be effective?Construct the 95% confidence interval estimate of the mean wake time for a population with the treatment.min

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Answered: A cdinical trial was conducted to test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A study compared the long-term results of two treatments: a modified Burch procedure, and a sling procedure for stress incontinence with a low-pressure urethra. Thirty-six women took part in the study with 19 in the Burch treatment group and 17 in the sling procedure treatment group. One of the outcome measures at three months post-surgery was maximum urethral closure pressure (cm H2O). In the Burch group the mean and standard deviation were 16.4 and 8.2 cm, respectively. In the sling group, the mean and standard deviation were 39.8 and 23.0, respectively. Construct the 99% confidence interval for the difference in mean maximum urethral closure pressure for the two populations represented by these subjects. What is the critical value of the confidence interval for difference in means? what is the lower bound of a 99% confidence interval for the difference in means? (Burch-Sling) what is the upper bound of a 99% confidence interval for the difference in means? (Birch-Sling)
A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is less than the mean of WaxCo. In a random sample of 18 floors of WaxWin and 10 of WaxCo. WaxWin had a mean lifetime of 22.1 with a standard deviation of 5.6 and WaxCo had a mean lifetime of 28.5 with a standard deviation of 7.1. Perform a hypothesis test using a significance level of 0.05 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: O Ho: H1 µ2(claim) O Ho: µ1 2 H2 HA: H1 < µ2(claim) O Ho: µ1 = µ2 HA: H1 7 M2(claim) Since the level of significance is 0.05 the critical value is -1.751 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that the mean of WaxWin is less than the mean of WaxCo. O There is not enough evidence to reject the claim that the mean of…
According to a research study, college students spent 24.2 hours doing homework per week last year, on average. A random sample of 16 college students was surveyed and the mean amount of time per week each college student spent on homework was 23.7. This data has a sample standard deviation of 2.2. (Assume that the scores are normally distributed.) Researchers conduct a one-mean hypothesis at the 1% significance level, to test if the mean amount of time college students spend on homework per week is less than the mean amount of time last year. Which answer choice shows the correct null and alternative hypotheses for this test? Select the correct answer below: H0:μ=24.2; Ha:μ>24.2, which is a right-tailed test. H0:μ=24.2; Ha:μ<24.2, which is a left-tailed test. H0:μ=23.7; Ha:μ>23.7, which is a right-tailed test. H0:μ=23.7; Ha:μ<23.7, which is a left-tailed test.
It is known that the zinc concentrations are usually normally distributed and havea variance of 0.09 grams per milliliter squared. In a study, the average zinc concentrationsrecovered from a random sample of zinc measurements in 22 different locations was found tobe 2.6 grams per milliliter. Calculate and interpret a 90% confidence interval for the overallaverage zinc concentration.
A veterinarian wants to perform a study at a local animal shelter where 200 dogs need training on behavior modification. The purpose of the study would be to determine if using a firm voice during training for 10 minutes improves a dog's learning behavior compared to not speaking during training for 10 minutes. Part A: Describe an appropriate design for the study. Part B: The hypotheses for this study are as follows: Ho: There is no difference in the mean improvement of dogs during behavior modification for either treatment. Ha: The mean improvement of dogs during behavior modification is greater for the firm voice treatment. The shelters will allow trainers to use a firm voice during training if the null hypothesis is rejected. What are the possible Type I and II errors? Describe the consequences of each in the context of this study and discuss which type you think is more serious.n
You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? You were told that the mean daily cost of a hotel room in downtown St. Louis is $120. You will be needing to rent a hotel room there in the near future and you want to find the best rate. You randomly select a sample of 18 hotel rooms and find that the average cost is $121.33 with a standard deviation of $18.046. At the α = 0.05 significance level, determine if there is enough evidence to reject the claim. What is the decision for this hypothesis test? Reject the null because the test statistic is in the critical region and the…
Hoaglin, Mosteller, and Tukey (1983) presented data on blood levels of beta-endorphin as a function of stress. They took beta-endorphin levels for 19 patients 12 hours before surgery and again 10 minutes before surgery. The data are presented below, in fmol/ml Construct a 95% confidence limits on the true mean difference between endorphin levels at the two times described. Participant 12 hours before 10 minutes before 1 10 6.5 2 6.5 14.0 3 8.0 13.5 4 12 18 5 5.0 14.5 6 11.5 9.0 7 5.0 18.0 8…
A researcher wonders whether the recession has changed variability in family size in his city. Before the recession, the mean was 3.7 and the standard deviation was 1.76. The researcher randomly selects 41 families from a population that is normally distributed. His sample has a mean of 3.1 and a standard deviation of 1.45. Test the claim that the standard deviation in size has changed at the αα=.05 significance level.
According to the U.S. Department of Transportation’s Air Travel Consumer Report, the nation’s 12 largest airlines recorded an on-time arrival percentage of 77.4% in 2001. Of interest is to estimate the mean delay time for the 22.6% of all flights that did not arrive on time during 2013. A simple random sample of 28 late arriving flights was selected, and the mean delay time of this sample of 28 flights was 14.2 minutes, with a sample standard deviation of s= 6.4 minutes. Use this information to calculate and interpret a 98% confidence interval for the mean delay time for all flights that did not arrive on time during 2013.
A small pilot study is run to compare a new drug for chronic pain to one that is currently available. Participants are randomly assigned to receive either the new drug or the currently available drug and report improvement in pain on a 5-point ordinal scale: 1=Pain is much worse, 2=Pain is slightly worse, 3= No change, 4=Pain improved slightly, 5=Pain much improved. Is there a significant difference in self-reported improvement in pain? Use the Mann-Whitney U test with a 5% level of significance. Please show work. New Drug: 4 5 3 3 4 2 Standard Drug: 2 3 4 1 2 3
Prices of basic commodities are often greatly affected by typhoons. During the aftermath of recent typhoon, the prices of tilapia were reported to have been sold at ₱20 – ₱25 more per kilogram at local wet markets. However, the price was back to its normal mean price at ₱100 per kilo one week after. If a random sample of 10 tilapia sales transactions from local wet markets have prices (in pesos per kilo) of 107, 115, 130, 95, 100, 105, 98, 116, 104, 100. Assuming that the tilapia prices are normally distributed, is there sufficient evidence to say that the mean price of tilapia in these markets is greater than ₱100? Use a 0.05 level of significance. State the null and alternative hypotheses: Ho: ________ (symbols) Ho: _______________________________ (statement) Ha: _________ (symbols) Ha: _______________________________ (statement)
A large p-value indicates that the data is consistent with the alternative hypothesis. True or false?

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