A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H of 33.0 m above sea level, directed at an angle e above the horizontal with an unknown speed vo. The projectile remains in flight for 6.00 seconds and travels a horizontal distance D of 145.0 m. Assuming that air friction can be neglected, calculate the value of the angle 0. 55.299° You know how long the rock is in the air. This yields its horizontal velocity from the horizontal distance it travels. You get the vertical component of the velocity by using the equation of motion with constant acceleration. From the two velocity components you can figure out the angle. Incorrect. Tries 9/10 Previous Tries Submit Answer Calculate the speed at which the rock is launched. 34.93m/s You know the net change in height of the rock, along with the horizontal distance it travels. Since you calculated the initial angle already, you can use your equations of position in two dimensions to solve for the initial speed. Incorrect. Tries 2/10 Previous Tries To what height above sea level does the rock rise? Submit Answer Submit Answer Tries 0/10
A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H of 33.0 m above sea level, directed at an angle e above the horizontal with an unknown speed vo. The projectile remains in flight for 6.00 seconds and travels a horizontal distance D of 145.0 m. Assuming that air friction can be neglected, calculate the value of the angle 0. 55.299° You know how long the rock is in the air. This yields its horizontal velocity from the horizontal distance it travels. You get the vertical component of the velocity by using the equation of motion with constant acceleration. From the two velocity components you can figure out the angle. Incorrect. Tries 9/10 Previous Tries Submit Answer Calculate the speed at which the rock is launched. 34.93m/s You know the net change in height of the rock, along with the horizontal distance it travels. Since you calculated the initial angle already, you can use your equations of position in two dimensions to solve for the initial speed. Incorrect. Tries 2/10 Previous Tries To what height above sea level does the rock rise? Submit Answer Submit Answer Tries 0/10
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H of 33.0 m above sea level, directed at an angle e above the horizontal with
an unknown speed vo.
The projectile remains in flight for 6.00 seconds and travels a horizontal distance D of 145.0 m. Assuming that air friction can be neglected, calculate the value of the angle 0.
55.299°
You know how long the rock is in the air. This yields its horizontal velocity from the horizontal distance it travels. You get the vertical component of the velocity by using the equation of motion with constant
acceleration. From the two velocity components you can figure out the angle.
Incorrect. Tries 9/10 Previous Tries
Submit Answer
Calculate the speed at which the rock is launched.
34.93m/s
You know the net change in height of the rock, along with the horizontal distance it travels. Since you calculated the initial angle already, you can use your equations of position in two dimensions to solve
for the initial speed.
Incorrect. Tries 2/10 Previous Tries
To what height above sea level does the rock rise?
Submit Answer
Submit Answer Tries 0/10
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Kinematic expression for horizontal distance traveled
VIEWKinematic expression for vertical distance traveled
VIEWDivide equation 2 by 1
VIEWSubstitution
VIEWSubstitute the angle, time of flight and range in equation (1)
VIEWThe velocity at the maximum height
VIEWSubstitution
VIEWThe height above the sea level
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