C.Calculate the velocity of the shell as it hits the target. Report your answer inmagnitude-angle notation. An artillery unit is conducting a fire mission on an enemy observation post located ahorizontal distance of 8.72 km away from the firing position. The unit fires a shellwith a speed of 243 m/s oriented at an angle of 17.8 above the horizontal.Assume that the shell hits the target and that air resistance is negligible.Calculate the time it takes the shell to reach the target.7Dporozontilen de 8.72 km = 8.72 x 10³ m0 = 17.8Ul=Q43k. time it takes shell to reach torgetysics: V₂-sin)V₂ = 1 c05 (0)dre: d = 4 cos (0)11.3147 (05/17,8 ) x +

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C. Calculate the velocity of the shell as it hits the target. Report your answer in magnitude-angle notation.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Proper Length

The theory of special relativity explains the connection between space and time to objects that move in a straight line at a constant speed. The objects move at the speed of light. When an object approaches light speed, its mass is endless and cannot move faster than light. The most crucial postulate of Einstein's special relativity is that the laws of nature do not change in each frame of reference.

Question

C.
Calculate the velocity of the shell as it hits the target. Report your answer in
magnitude-angle notation.

An artillery unit is conducting a fire mission on an enemy observation post located a
horizontal distance of 8.72 km away from the firing position. The unit fires a shell
with a speed of 243 m/s oriented at an angle of 17.8 above the horizontal.
Assume that the shell hits the target and that air resistance is negligible.
Calculate the time it takes the shell to reach the target.
7
D
porozontil
en de 8.72 km = 8.72 x 10³ m
0 = 17.8
Ul=Q43
k. time it takes shell to reach torget
ysics: V₂-sin)
V₂ = 1 c05 (0)
dre: d = 4 cos (0)
11.3
147 (05/17,8 ) x +

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