A car is accelerated from velocity v₁ to v2 in the time period of t. The mass of the car is m. The inclined angle of the hill is a. The distance travelled along the hill is L. The vertical distance travelled is H. If v1= 2 m/s, v2 = 30 m/s, t = 5 s, m= 1000 kg, a = 30°, L = 50 m, calculate the extra power, W=_ H W

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A car is accelerated from velocity vto v2 in the time period of t . The mass of the car is m. The inclined angle of the hill is α. The distance travelled along the hill is L. The vertical distance travelled is H.

If v1= 2 m/s, v2 = 30 m/s, t = 5 s, m= 1000 kg, α = 30 °, L = 50 m, calculate the extra power , =_____W



 

**Description of the Problem:**

A car is accelerated from velocity \( v_1 \) to \( v_2 \) in the time period of \( t \). The mass of the car is \( m \). The inclined angle of the hill is \( \alpha \). The distance travelled along the hill is \( L \). The vertical distance travelled is \( H \).

**Given Values:**

- Initial velocity, \( v_1 = 2 \, \text{m/s} \)
- Final velocity, \( v_2 = 30 \, \text{m/s} \)
- Time, \( t = 5 \, \text{s} \)
- Mass, \( m = 1000 \, \text{kg} \)
- Incline angle, \( \alpha = 30^\circ \)
- Distance along the hill, \( L = 50 \, \text{m} \)

Calculate the extra power, \( \dot{W} = \, \_\_\_\_ \, \text{W} \).

**Diagram Explanation:**

- The diagram shows a car on an inclined plane with angle \(\alpha\).
- The plane's surface is labeled \(L\), which represents the distance travelled along the incline.
- The vertical distance travelled is labeled \(H\).

**Problem Requirements:**

Use the above information to calculate the extra power \( \dot{W} \) required for the car's motion up the incline.

**Steps:**

1. Calculate the increase in kinetic energy.
2. Calculate the increase in potential energy.
3. Determine the total work done and then the extra power required.

This explanation will guide students to understand how to approach the problem by considering both kinetic and potential energy changes while moving up an inclined plane.
Transcribed Image Text:**Description of the Problem:** A car is accelerated from velocity \( v_1 \) to \( v_2 \) in the time period of \( t \). The mass of the car is \( m \). The inclined angle of the hill is \( \alpha \). The distance travelled along the hill is \( L \). The vertical distance travelled is \( H \). **Given Values:** - Initial velocity, \( v_1 = 2 \, \text{m/s} \) - Final velocity, \( v_2 = 30 \, \text{m/s} \) - Time, \( t = 5 \, \text{s} \) - Mass, \( m = 1000 \, \text{kg} \) - Incline angle, \( \alpha = 30^\circ \) - Distance along the hill, \( L = 50 \, \text{m} \) Calculate the extra power, \( \dot{W} = \, \_\_\_\_ \, \text{W} \). **Diagram Explanation:** - The diagram shows a car on an inclined plane with angle \(\alpha\). - The plane's surface is labeled \(L\), which represents the distance travelled along the incline. - The vertical distance travelled is labeled \(H\). **Problem Requirements:** Use the above information to calculate the extra power \( \dot{W} \) required for the car's motion up the incline. **Steps:** 1. Calculate the increase in kinetic energy. 2. Calculate the increase in potential energy. 3. Determine the total work done and then the extra power required. This explanation will guide students to understand how to approach the problem by considering both kinetic and potential energy changes while moving up an inclined plane.
Expert Solution
Step 1

Given that

The mass of the car is m=1000kg

the initial velocity of the car is v1=2m/s

the final velocity of the car is v2=30m/s

the time taken by the car to achieve its final velocity is t=5s

the distance traveled by car is L=50m

and the angle of inclination of the inclined plane is α=30o

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