A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? K (J) KoF x (m) Number i 3.345 Unit m/s

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Chapter1: Units, Trigonometry. And Vectors
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Your answer is partially correct.
A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force
directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x
as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the
object moves back through x = -3.4 m?
К ()
Ko
·x (m)
Number
i
3.345
Unit
m/s
eTextbook and Media
GO Tutorial
Transcribed Image Text:Your answer is partially correct. A 5.9 kg object is moving in the positive x direction. When it passes through x = 0, a constant force directed along the axis begins to act on it. The figure here gives its kinetic energy K versus position x as it moves from x = 0 to x = 5.0 m; Ko = 29 J. The force continues to act. What is speed v when the object moves back through x = -3.4 m? К () Ko ·x (m) Number i 3.345 Unit m/s eTextbook and Media GO Tutorial
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