A 687-kg elevator starts from rest and moves upward for 2.90 s with constant acceleration until it reaches its cruising speed, 1.81 m/s. (a) What is the average power of the elevator motor during this period? ____________hp (b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with constant speed.) _____________hp

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A: Given,mass of the car, m = 710 kgspeed of the car, v = 23 msdrag force, F = 500 Nslope of the…

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A: Given data:  Mass (m) = 65.0 kg Distance (d) = 5.00 m Frictional force (f) = 75.0 N g = 10.0 m/s2…

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A: To solve the problem we will use work-energy theorem. Given Data Mass of the cabinet is m=65.0 kg…

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A: Mass of the person = 189 poundsHeight of the ladder = 3 metersTime = 6.3 seconds

Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…

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A: Given  Mass of object, M = 10 kg  Force, F = 60 N  Angle = 45 degree  Coefficient of kinetic…

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A: given: height of ramp h = 2m mass of block m = 50 kg height at point p h' = 0.5 m