A capacitor of capacitance C is charged to an electric potential difference of magnitude V+ and connected to an inductor of inductance L. Find the maximum current in the circuit. CV²./L zero Limax²/2 c²v². (CV2/L)0.5 imax
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- Circuit II has twice the inductance and one‑half the capacitance of Circuit I. If the resistor in Circuit II is replaced with a resistor that has twice the resistance, what is the ratio of the resonant frequencies of Circuit I to Circuit II?An electric current contains a battery that produces a voltage of 60 voltsV , a resistor with a resistance of 13 ohms, and inductor with an inductance of 5 henrys H . Using calculus, it can be shown that I I t (in amperes, A), when t seconds after the switch is closed is 13 5 60 1 13 t I e 1.4.1 Use this equation to express the time t as function of the currentI 1. b) Write down the second order ordinary differential equation that represents the electric circuit. Where R = 302, C=1/7 F, L = 4 H, and the voltage source E(t) = 110 Sin377t DO NOT SOLVE THE SYSTEM FOR CURRENT. R www C E(t) = Esin ot еее
- The charge on the capacitor of an LC circuit with capacitance C and inductance L obeys the following equation. Find the maximum current in the circuit. q= Q cos [t/(LC)0.5] Q Q/(LC) 0.5 zero QQ²/(LC) 0.5 imax 1/(LC) 0.5An LC circuit has an inductance of L mH and a capacitance of (5.905x10^-3) mF. At one instant the charge on the capacitor is (8.1403x10^-3) mC. What is the voltage in this circuit, at that time? Express your result in V. Provide your answer with four significant figures.