(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 6.00 x 10 kg hangs motionless on it. (Enter a number.) 0.000588 ✓ N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0⁰- T₁ TR T₁ To -5.0° Ⓡ The strand sags at an angle of 12.0° below the horizontal. (Enter a number.) 0.000588 N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) = 4.808 X

(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 6.00 x 10 kg hangs motionless on it. (Enter a number.) 0.000588 ✓ N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0⁰- T₁ TR T₁ To -5.0° Ⓡ The strand sags at an angle of 12.0° below the horizontal. (Enter a number.) 0.000588 N Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand)/(tension in vertical strand) = 4.808 X

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter5: Newton's Laws Of Motion

Section: Chapter Questions

Problem 76PQ: Jamal and Dayo are lifting a large chest, weighing 207 lb, by using the two rope handles attached to...

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Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 6.00 x 10-5 kg hangs motionless on it. (Enter a number.)
0.000588
N
(b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure.
5.0⁰
TR
T. Ta
W
5.0°
i
The strand sags at an angle of 12.0° below the horizontal. (Enter a number.)
0.000588
N
Compare this with the tension in the vertical strand (find their ratio). (Enter a number.)
(tension in horizontal strand)/(tension in vertical strand) = 4.808

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