Attached the question with the associated equation. Struggling to understand the jomega 3.4 Standard second-order responses3.23 (a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in thestandard form H (jw) = HOBP HBP. (b) Show that no matter how you select w, and @H,the Q of that filter can never exceed. This is why the filter is called wideband. this is a second-order filter, we have chosen to discuss it here to demonstrate theindicating a zero at the origin and two real poles at -1/R₁C₁ and -1/R2C2. Thoughuse of lower-order building blocks to synthetize higher-order filters. Letting s→ jw First-Order Active129SECTION 3.2yields1346(3.29a)H(jw) = Hojw/wL(1 + jw/wL)(1 + jw/wH).

The frequency response function of a second-order filter is given asTowrite the frequency response…

Answered: (a) By proper manipulation, put the…

Introductory Circuit Analysis (13th Edition)

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ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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Attached the question with the associated equation. Struggling to understand the jomega

3.4 Standard second-order responses
3.23 (a) By proper manipulation, put the wideband band-pass function of Eq. (3.29a) in the
standard form H (jw) = HOBP HBP. (b) Show that no matter how you select w, and @H,
the Q of that filter can never exceed. This is why the filter is called wideband.

this is a second-order filter, we have chosen to discuss it here to demonstrate the
indicating a zero at the origin and two real poles at -1/R₁C₁ and -1/R2C2. Though
use of lower-order building blocks to synthetize higher-order filters. Letting s→ jw First-Order Active
129
SECTION 3.2
yields
1346
(3.29a)
H(jw) = Ho
jw/wL
(1 + jw/wL)(1 + jw/wH).

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The frequency response function of a second-order filter is given as

$H open parentheses j omega close parentheses equals H subscript 0 fraction numerator bevelled fraction numerator j omega over denominator omega subscript L end fraction over denominator open parentheses 1 plus bevelled fraction numerator j omega over denominator omega subscript L end fraction close parentheses open parentheses 1 plus bevelled fraction numerator j omega over denominator omega subscript H end fraction close parentheses end fraction space space space... open parentheses 1 close parentheses.$

write the frequency response function in the following standard form $H open parentheses j omega close parentheses equals H subscript 0 B P end subscript H subscript B P end subscript$ and
prove that the quality-factor of the wideband bandpass filter is always $1 half$ irrespective of values of $omega subscript L$ and $omega subscript H.$

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