A buffer solution is made using a weak acid, HA, with a pK, of 5.18. If the ratio of [A] to [HA] is 0.10, what is the pH of the buffer? pH =

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**Buffer Solution pH Calculation**

A buffer solution is made using a weak acid, HA, with a \( pK_a \) of 5.18. If the ratio of \([A^-]\) to \([HA]\) is 0.10, what is the pH of the buffer?

**pH =** [Input box for answer] 

*Explanation:*

To calculate the pH of the buffer solution, the Henderson-Hasselbalch equation is used:

\[ \text{pH} = pK_a + \log \left( \frac{[A^-]}{[HA]} \right) \]

Where:
- \( pK_a \) is the negative logarithm of the acid dissociation constant
- \([A^-]\) and \([HA]\) are the concentrations of the conjugate base and the weak acid, respectively

Given values:
- \( pK_a = 5.18 \)
- Ratio \([A^-]/[HA] = 0.10\)
Transcribed Image Text:**Buffer Solution pH Calculation** A buffer solution is made using a weak acid, HA, with a \( pK_a \) of 5.18. If the ratio of \([A^-]\) to \([HA]\) is 0.10, what is the pH of the buffer? **pH =** [Input box for answer] *Explanation:* To calculate the pH of the buffer solution, the Henderson-Hasselbalch equation is used: \[ \text{pH} = pK_a + \log \left( \frac{[A^-]}{[HA]} \right) \] Where: - \( pK_a \) is the negative logarithm of the acid dissociation constant - \([A^-]\) and \([HA]\) are the concentrations of the conjugate base and the weak acid, respectively Given values: - \( pK_a = 5.18 \) - Ratio \([A^-]/[HA] = 0.10\)
Expert Solution
Step 1

Given:

The pKa of the weak acid HA = 5.18

The ratio of [A-] to [HA] = 0.10

We have to find the pH of the buffer made by using the weak acid HA.

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