A boy stands on a cliff edge and throws a stone vertically upwards at timet = 0. The stone leaves his hand at 20ms-, Take the acceleration of theball as 9.81 ms.%3DShow that the equation for the displacement of the ball is:s= 201 - 4.9tab.Calculate the height of the stone 2.0s after release and 6.0safter release.Calculate the time taken for the stone return to the level of theboy's hand. You may assume the boy's hand does not move verticallyafter the ball is released.[Tota

Equations of kinematics for uniformly accelerated motion are given by, 1. v=u+at2. s=ut+12at23.…

A boy stands on a cliff edge and throws a stone vertically upwards at time t = 0. The stone leaves his hand at 20 ms. Take the acceleration of the ball as 9.81 ms. Show that the equation for the displacement of the ball is: s= 201 – 4.91 Calculate the height of the stone 2.0s after release and 6.0s after release. Calculate the time taken for the stone return to the level of the boy's hand. You may assume the boy's hand does not move vertically after the ball is released. Tot

A boy stands on a cliff edge and throws a stone vertically upwards at time t = 0. The stone leaves his hand at 20 ms. Take the acceleration of the ball as 9.81 ms. Show that the equation for the displacement of the ball is: s= 201 – 4.91 Calculate the height of the stone 2.0s after release and 6.0s after release. Calculate the time taken for the stone return to the level of the boy's hand. You may assume the boy's hand does not move vertically after the ball is released. Tot

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Relative Velocity

It is a measurement of an object with regards to the other object which is moving or stable or stationary. For example, if we are traveling in a bus and the bus is moving at speed of 50km/hr, then our speed is according to the nearby passenger on the bus is zero. According to them, we are not moving. But if one person standing on the ground or road observes us from outside of the bus, according to him we are moving at a speed of 50km/hr and the bus is also moving at a speed of 50km/hr. Now, the motion is recognized by the observer, it depends on a frame of reference or observer. This is motion called relative motion.

Question

A boy stands on a cliff edge and throws a stone vertically upwards at time
t = 0. The stone leaves his hand at 20ms-, Take the acceleration of the
ball as 9.81 ms.
%3D
Show that the equation for the displacement of the ball is:
s= 201 - 4.9t
a
b.
Calculate the height of the stone 2.0s after release and 6.0s
after release.
Calculate the time taken for the stone return to the level of the
boy's hand. You may assume the boy's hand does not move vertically
after the ball is released.
[Tota

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