Two particles move along an x axis. The position of particle 1 is given by x = 10.0t² +6.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 24.0 m/s. When the velocities of the particles match, what is their velocity? Number i Units
Two particles move along an x axis. The position of particle 1 is given by x = 10.0t² +6.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 24.0 m/s. When the velocities of the particles match, what is their velocity? Number i Units
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Step 1
Given,
The position of particle 1,
The velocity is,
At t=0 the particle velocity, v=24m/s
Acceleration of the particle 2,
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