Two particles move along an x axis. The position of particle 1 is given by x = 10.0t² +6.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 24.0 m/s. When the velocities of the particles match, what is their velocity? Number i Units

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Two particles move along an x axis. The position of particle 1 is given by x = 10.0t² +6.00t + 5.00 (in meters and seconds); the
acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 24.0 m/s. When
the velocities of the particles match, what is their velocity?
Number
i
Units
Transcribed Image Text:Two particles move along an x axis. The position of particle 1 is given by x = 10.0t² +6.00t + 5.00 (in meters and seconds); the acceleration of particle 2 is given by a = -9.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 24.0 m/s. When the velocities of the particles match, what is their velocity? Number i Units
Expert Solution
Step 1

Given,

The position of particle 1, x=10t2+6t+5

The velocity is,

v=dxdtv=ddt10t2+6t+5v=20t+6

At t=0 the particle velocity, v=24m/s

Acceleration of the particle 2,

a=-9tdvdt=-9t24udv=0t-9tu-24=-9t22u=24-4.5t2

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