A body of mass 2.0 kg is moving along the x-axis with a speed of 3.0 m/s at the instant represented below. (a) What is the acceleration of the body F3 1LL 30° F₁ 37° F₁ = 50.0 N F₂ = 30.0 N F3 = 80.0 N
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- Falcons are excellent fliers that can reach very high speeds by diving nearly straight down. To pull out of such a dive, a falcon extends its wings and flies through a circular arc that redirects its motion. The forces on the falcon that control its motion are its weight and an upward lift force—like an airplane—due to the air flowing over its wings. At the bottom of the arc, as shown, a falcon can easily achieve an acceleration of 15 m/s2. A falcon starts from rest, does a free-fall dive from a height of 30 m, and then pulls out by flying in a circular arc of radius 50 m. Which segment of the motion has a higher acceleration?A. The free-fall diveB. The circular arcC. The two accelerations are equal.A 12 kg meteor experiences an acceleration of 7.2 m/s*2, when falling towards the earth. a) How high above the earth's surface is the meteor? b) What force will a 30 kg meteor experience at the same altitude?In the following diagram a block is placed on an inclined plane. The mass of the block is 10.0 kg an the incline angle is 18. Determine the acceleration if u = 0.32 when the block start to slide down 1 m/s/s O 0.039 m/s/s 0.28 m/s/s O 0.046 m/s/s 0.057 m/s/s
- Determine the force Q-> when the block moves with constant velocity. Express your answer in vector form.Question 20, Physics - equation sheet attachedYou place a crate of mass 47.7 kg on a frictionless 3.61-meter-long incline. You release the crate from rest, and it begins to slide down, eventually reaching the bottom 1.15 s after you released it. What is the angle of the incline? 1 50.7 degrees 76.1 degrees 3. 42.3 degrees 4 33.8 degrees
- A car of mass 822 kg is traveling 26.4 m/a when the driver applies the brakes, which lock the wheels. The car skids for 4.47 s in the positive x direction before coming to rest. What is the cars acceleration in m/ s2? what magnitude force in N acted on the car during this time? How far in m did the car travel?A woman pulls a cloth out from under a 200 g bowl sitting on a table. The bowl is 30.0 cm from the far edge of the cloth, and the cloth exerts a friction force of 0.125 N on the bowl. Assume the cloth is pulled with a constant horizontal acceleration of 2.80 m/s2. What distance (in m) does the bowl travel relative to the top of the table? (Assume the cloth moves in the +x-direction and notice that it moves more than 30.0 cm relative to the top of the table.)A rope is attached to Box A, and it is pulled on a rough surface due east with friction. The mass of Box A is 50 kg, and the tension force applied to the box is 100 N due east. If Box A is pulled by the tension force for 4.0 s, and the velocity changes from 0.1 m/s due east to 0.65 m/s due east during the time Box A is pulled, answer the following questions. (a) What is the acceleration of Box A during the time it is pulled? (b) What is the change in kinetic energy of Box A during the time it is pulled? (c) What is the net work done on Box A by the tension force and the frictional force together? (d) What is the work done on Box A by the tension force alone? (e) What is the work done on Box A by the frictional force alone?
- A car moves along a horizontal road with constant velocity VO,z i (44 m/s) i Vo = until it encounters a smooth inclined hill. It climbs the hill with constant velocity Ủ1 = V1,z î + V1‚y Ĵ = (38 m/s)i + (4.2 m/s) j as indicated in the figure. The period of time during which the car changes its velocity is At = 3.6 s. Y Part (a) Enter a symbolic expression for the average acceleration vector of the car during the given time period in terms of the variables in the problem and the standard unit vectors. Part (b) What is the magnitude, in meters per squared second, of the car's acceleration during the given time period.FTA FTB mA = 8.0 kg mg 10.0 kg 619 32° FTA = FTB for a pully with negligible mass as and friction. What are FTA = FTB ? Give your answer in Newtons to the correct number of significant figures. Remember: For a problem like this, an FBD is required on the midterm!Falcons are excellent fliers that can reach very high speeds by diving nearly straight down. To pull out of such a dive, a falcon extends its wings and flies through a circular arc that redirects its motion. The forces on the falcon that control its motion are its weight and an upward lift force—like an airplane—due to the air flowing over its wings. At the bottom of the arc, as shown, a falcon can easily achieve an acceleration of 15 m/s2. Suppose the falcon weighs 8.0 N and is turning with an acceleration of 15 m/s2 at the lowest point of the arc. What is the magnitude of the upward lift force at this instant?A. 8.0 N B. 12 NC. 16 N D. 20 N