An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the depth of the crater? 32 m 10 m 26 m 14 m 86 m
An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the depth of the crater? 32 m 10 m 26 m 14 m 86 m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:An astronaut stands by the rim of a crater on the moon, where the acceleration of
gravity is 1.62 m/s². To determine the depth of the crater, she drops a rock and
measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the
depth of the crater?
O 32 m
10 m
26 m
14 m
86 m
Expert Solution

Given data
Given data :
Acceleration of gravity ( g ) = 1.62 m/s2
Time taken ( t ) = 10.3 s
Initial velocity of rock ( u ) = 0 m/s
To find :
Depth of the crater ( s ) = ?
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