An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the depth of the crater? 32 m 10 m 26 m 14 m 86 m

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Chapter1: Units, Trigonometry. And Vectors
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An astronaut stands by the rim of a crater on the moon, where the acceleration of
gravity is 1.62 m/s². To determine the depth of the crater, she drops a rock and
measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the
depth of the crater?
O 32 m
10 m
26 m
14 m
86 m
Transcribed Image Text:An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s². To determine the depth of the crater, she drops a rock and measures the time it takes for it to hit the bottom. If the time is 10.3 s, what is the depth of the crater? O 32 m 10 m 26 m 14 m 86 m
Expert Solution
Given data

Given data :

Acceleration of gravity ( g ) =  1.62 m/s2

Time taken ( t ) = 10.3 s 

Initial velocity of rock ( u ) = 0 m/s

 

 

To find :

Depth of the crater ( s ) = ?

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