initially at rest on the surface of Mars where g = 4 m/s ^ 2 . The mass of the spaceship is 3000 kg. The engines ignite and there is an upward thrust force on the spaceship . After a period of 25 seconds of constant thrust, the spaceship has reached a velocity of the 600 m/s.

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Chapter1: Units, Trigonometry. And Vectors
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A spaceship is initially at rest on the surface of Mars where g = 4 m/s ^ 2 . The mass of the spaceship is 3000 kg. The engines ignite and there is an upward thrust force on the spaceship . After a period of 25 seconds of constant thrust, the spaceship has reached a velocity of the 600 m/s. 

what is the acceleration?

 

What is the altitude of the spaceship at 25 seconds? 

Expert Solution
Step 1

We know that initially, the spaceship rests on the surface of mars and where g = 4 m/s2 and the mass of the spaceship is m, and after the time t, the velocity of the spaceship is v  m/s. 

So we know that the first equation of motion is given as 

v=u+at  ----------- eq1 

where  u is the initial velocity 

a is the acceleration 

t is time 

We know that the second equation of the motion is given as

s= ut +12at2 --------------- eq2 

wheres is the altitude of the spaceship at the time t 

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