A body is traveling at 4.00 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion separates the body into two parts, each of 4.00 kg, and increases the total kinetic energy by 64.0J. The forward part continues to move in the original direction of motion. What are the speeds of the rear part and the forward part?
A body is traveling at 4.00 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion separates the body into two parts, each of 4.00 kg, and increases the total kinetic energy by 64.0J. The forward part continues to move in the original direction of motion. What are the speeds of the rear part and the forward part?
Related questions
Question
I would appreciate any and all assistance with this question!
![A body is traveling at 4.00 m/s along the positive direction of an x axis; no net force acts on the body.
An internal explosion separates the body into two parts, each of 4.00 kg, and increases the total kinetic
energy by 64.0 J. The forward part continues to move in the original direction of motion. What are the
speeds of the rear part and the forward part?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f7679a1-29bd-41dc-b06e-05edfd912e91%2Faf2bfe77-229b-4abb-977d-2f4ff5d9c0e3%2Fgxa6lci_processed.png&w=3840&q=75)
Transcribed Image Text:A body is traveling at 4.00 m/s along the positive direction of an x axis; no net force acts on the body.
An internal explosion separates the body into two parts, each of 4.00 kg, and increases the total kinetic
energy by 64.0 J. The forward part continues to move in the original direction of motion. What are the
speeds of the rear part and the forward part?
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given:
v=4 m/s
m=4 kg
KEi=64J
Step 2
Formula used:
Where
m=mass
v=velocity
KE= kinetic energy
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)