A bob of mass m is suspended from point O by a massless string of length I as shown. At the bottommost point it is given a velocity u = √/12gl for 1 = 1m and m = 1kg, match the following two columns when string becomes horizontal (g = 10ms) List 1 Speed of bob Acceleration of bob 0. I List 2 10 20 U Tension in string Tangential acceleration of bob None 100

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Chapter1: Units, Trigonometry. And Vectors
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A bob of mass m is suspended from point O by a massless string of length I as shown.
At the bottommost point it is given a velocity u=√12gl for 1 = 1m and m= 1kg, match
the following two columns when string becomes horizontal (g = 10ms)
List 1
Speed of bob
Acceleration of bob
I
List 2
10
20
U
Tension in string
Tangential acceleration of bob None
100
Transcribed Image Text:A bob of mass m is suspended from point O by a massless string of length I as shown. At the bottommost point it is given a velocity u=√12gl for 1 = 1m and m= 1kg, match the following two columns when string becomes horizontal (g = 10ms) List 1 Speed of bob Acceleration of bob I List 2 10 20 U Tension in string Tangential acceleration of bob None 100
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