A 15 mg object with an initial velocity of 5.7 m/s is acted on by a force, as shown in the graph attached. What is the magnitude of the object’s velocity when the force has stopped acting on it?
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- NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The subway train shown is traveling at a speed of 38 mi/h when the brakes are fully applied on the wheels of car A, causing it to slide on the track, but the brakes are not applied on the wheels of cars B or C. 40 tons B The force FAB is 19.388 The force FBC is 50 tons ‒‒‒‒‒ C Knowing that the coefficient of kinetic friction is 0.35 between the wheels and the track, determine the force in each coupling. 40 tons lb Compression 8.6 lb CompressionAfter falling from rest from a height of 29 m, a 0.45-kg ball rebounds upward, reaching a height of 19 m. If the contact between ball and ground lasted 2.2 ms, what average force was exerted on the ball? (Enter the magnitude.) NThe block A with mass of 80 kg slides along the top of the block B with mass of 110 kg. The block A has an acceleration of 3.0 m/s2 when a horizontal force F of 700 N is applied, as in the Figure. There is no friction between the block B and a horizontal frictionless surface, but there is friction between the two blocks. Calculate the acceleration of the block A is going to B during the time that the block A remains in contact.
- The magnitude of the net force exerted in the negative x direction on a 9.6kg particle varies in time as shown in the Figure below. If initially the velocity of the particle is +4.8m/s along the x axis, determine the final velocity of the particle after the 5.0s interval. Please note that (+) and (-) signs are used to denote positive and negative directions along the a axis! Don't forget to use the correct sign in your answer. Express your answer in units of m/s using one decimal place. F(N) 5. 4. Þ t(s) 234 5 6This problem pertains to the scenario depicted in the diagram below, where the masses of the blocks are mi = 9.50 kg and m2 = 7.50 kg , and the angle of the ramp is 0 = 27.5°. There is no friction between block 2 and the ramp, but there is friction between block 1 and the flat surface it rests on. When the system is set in motion, both blocks move to the right at a constant speed. What is the coefficient of kinetic friction between block 1 and the flat surface (uk)? Show all steps, including drawing free body diagrams and applying Newton's 2nd law to each block. Problem 4 %3D sliding at constant speed m1 sliding at m2 constant friction no speed friction here hereThe magnitude of the net force exerted in the positive x direction on a 9.2kg particle varies in time as shown in the Figure below. If initially the velocity of the particle is +6m/s along the x axis, determine the final velocity of the particle after the 5.0s interval. Please note that (+) and (−) signs are used to denote positive and negative directions along the x axis! Don't forget to use the correct sign in your answer. Express your answer in units of m/sm/s using one decimal place.
- (The complete question is in the picture) Your professor kicks a soccer ball from the ground with mass m giving it an initial velocity of v0 and reaching a certain maximum height. You, wanting to get higher grades by showing off, kicks the ball and gives it an initial velocity that is double your professor’s shot. What is the maximum height of your shot compared to your professor’s? A. Your shot is 4 times higher than your prof’s shot. B. Your shot is 1/4 times higher than your prof’s shot. C. Your shot is 8 times higher than your prof’s shot. D. Your shot is 2 times higher than your prof’s shot.As shown in the figure, a woman is straining to lift a large crate, but without success because it is too heavy. We denote the forces on the crate as follows: P is the magnitude of the upward force being exerted on the crate by the person, C is the magnitude of the vertical contact force on the crate by the floor, and W is the weight of the crate. How are the magnitudes of these forces related while the person is trying unsuccessfully to lift the crate? OA P=C OB.P+C>W OCP+CDraw diagram or sketch to help you understand the situation. A 73kg runner starts walking at 3.4 m/s [E] and begins to speed up for 6.0 s, reaching a final velocity of 11.2 m/s [E]. Calculate the net force acting on the runner.Can you solve this question quickly please?The magnitude of the net force exerted in the negative x direction on a 9.6kg9.6kg particle varies in time as shown in the Figure below. If initially the velocity of the particle is +4.8m/s+4.8m/s along the x axis, determine the final velocity of the particle after the 5.0s5.0s interval. Please note that (+)(+) and (−)(−) signs are used to denote positive and negative directions along the xx axis! Don't forget to use the correct sign in your answer. Express your answer in units of m/sm/s using one decimal place.An object of mass 0.61 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed of 12.0 m/s. Find the magnitude (in N) of the average force acting on the object during the 2.9 ms time interval. (Enter a number.) _____________NSEE MORE QUESTIONSRecommended textbooks for youCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
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