Question #3 Can you please answer the below questions? Please do not skip any steps include ALL of your work and double check for accuracy. Thank you. A block of mass \( m = 5.64 \, \text{kg} \) is attached to a spring with spring constant \( k = 1542 \, \text{N/m} \) and rests on a frictionless surface. The block is pulled, stretching the spring a distance of \( 0.165 \, \text{m} \), and is held still. The block is then released and moves in simple harmonic motion about the equilibrium position. (Assume that the block is stretched in the positive direction.)(a) What is the frequency of this oscillation?\[ \boxed{ \, \, \, \, \, } \, \text{Hz} \](b) Where is the block located 3.24 s after it is released? (Give the displacement from the equilibrium. Include the sign of the value in your answer.)\[ \boxed{ \, \, \, \, \, } \, \text{m} \](c) What is the velocity of the mass at that time? (Indicate the direction with the sign of your answer.)\[ \boxed{ \, \, \, \, \, } \, \text{m/s} \]

Given, m=5.64 kgk=1542 N/m∆x=0.165 m(a) The frequency can be obtained by ω=kmω=15425.64ω=16.53 Hz2πf=ωf=16.532πf=2.63 Hz(b) x=∆xcosωtx=0.165cos16.53×3.24x=-0.098 mx is away from equilibrium (negative sign)(c) The velocity is v=dxdt=-∆xωsinωtv=-0.165×16.53×sin16.53×3.24v=-2.19 m/sv = 2.19 m/sv is towards equilibrium (positive sign)

Answered: A block of mass m= 5.64 kg is attached…