A block of mass m = 4.58kg moves along the x-axis subject to a net force which depends on position. The - 2.39 3) i. The block is initially at x = 0m moving with velocity = -3.72. (The input below will accept answers with no more than 1% variation from the correct value.) What is the smallest value of the block reaches? m Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for æ². force is Fnet (x) = (-3.22x – 2.3 What is the block's speed when it reaches x = 1.16m? m S
A block of mass m = 4.58kg moves along the x-axis subject to a net force which depends on position. The - 2.39 3) i. The block is initially at x = 0m moving with velocity = -3.72. (The input below will accept answers with no more than 1% variation from the correct value.) What is the smallest value of the block reaches? m Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for æ². force is Fnet (x) = (-3.22x – 2.3 What is the block's speed when it reaches x = 1.16m? m S
College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:A block of mass m = 4.58kg moves along the x-axis subject to a net force which depends on position.
The force is Fnet (x) = (-3.22 x − 2.39 Nx³) î.
The block is initially at x = 0m moving with velocity = -3.72₁.
(The input below will accept answers with no more than 1% variation from the correct value.)
What is the smallest value of a the block reaches?
m
Hint: Calculate the work done as a function of x, and then solve the resulting quadratic expression for ².
What is the block's speed when it reaches x = 1.16m?
m
S
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