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A binary tree with only one node has a height of 1. Questions: 1. At most how many and at least how many nodes can a binary tree of height 2016 have? Justify your answers. 2. Write a function Height(t) that, given a treet, returns its height. 3. Peter wants to check if a binary search treet is an AVL tree. Write a function ISAVL(t) that takes a binary search tree t as input and returns TRUE if the tree is an AVL tree (balanced) and FALSE otherwise.

A binary tree with only one node has a height of 1. Questions: 1. At most how many and at least how many nodes can a binary tree of height 2016 have? Justify your answers. 2. Write a function Height(t) that, given a treet, returns its height. 3. Peter wants to check if a binary search treet is an AVL tree. Write a function ISAVL(t) that takes a binary search tree t as input and returns TRUE if the tree is an AVL tree (balanced) and FALSE otherwise.

C++ Programming: From Problem Analysis to Program Design
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter17: Linked Lists
Section: Chapter Questions
Problem 6PE
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A binary tree with only one node has a height of 1. Questions: 1. At most how many and at least how many nodes can a binary tree of height 2016 have? Justify your answers. 2. Write a function Height(t) that, given a treet, returns its height. 3. Peter wants to check if a binary search treet is an AVL tree. Write a function ISAVL(t) that takes a binary search tree t as input and returns TRUE if the tree is an AVL tree (balanced) and FALSE otherwise.
Transcribed Image Text:A binary tree with only one node has a height of 1. Questions: 1. At most how many and at least how many nodes can a binary tree of height 2016 have? Justify your answers. 2. Write a function Height(t) that, given a treet, returns its height. 3. Peter wants to check if a binary search treet is an AVL tree. Write a function ISAVL(t) that takes a binary search tree t as input and returns TRUE if the tree is an AVL tree (balanced) and FALSE otherwise.
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