A bicycle tire is inflated to a gauge pressure of 30.0 psi ata temperature of t 5 0°C. What will its gauge pressure beat 32°C if the tire is considered nonexpandable? (Note:The gauge pressure is the difference between the tire pressure and atmospheric pressure, 14.7 psi.)
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A bicycle tire is inflated to a gauge pressure of 30.0 psi at
a temperature of t 5 0°C. What will its gauge pressure be
at 32°C if the tire is considered nonexpandable? (Note:
The gauge pressure is the difference between the tire pressure and atmospheric pressure, 14.7 psi.)
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- A container which is air tight has a volume of * 2 * 500L internal pressure of 1.0 atmosphere, internal temperature of 15 °C is washed off ythe deck of a ship located in the Philippine Trench, and sinks to a depth where the pressure is 175 atmosphere and the temperature is 3 °C. What would be the volume in m³ of the gas inside be when the container breaks under the pressure at this depth?An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 27.0% of its original volume and the temperature is increased to 39.0°C. (a) What is the tire pressure in pascals? Pa (b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. What is the new tire pressure (absolute) in pascals? PaTwo small containers, each with a volume of 125 cm3 contain helium gas at 17 ⁰F and 1.00 atm pressure. The two containers are joined by a small open tube of negligible volume allowing gas to flow from one container to the other. What common pressure will exist in the two containers if the temperature of one container is raised to 120 °F while the other container is kept at 17 °F?
- Step 1 (a) The ideal-gas equation describes each condition of the air in the tire. We will set up ratios in order to describe these changes. Dividing the equations PV = nRT in the initial and final states, we have PfVf Tf P¡Vi Ti Solving for the final pressure in the tire, gives Pf = = = which gives I Tf P(V)() P₁ Vf T₁ = (1.013 x 105 Pa) x 105 Pa. Note that the volume V¡ cancels out of the equation. = Vf Po = Pr (V ( ) ( ) Pd Pf Vi V₁ Step 2 (b) After the car is driven, the temperature and volume of air in the tire have changed. Let Td be the temperature and Vd be the volume of air in the tire. We have PdVd Td PfVf Tf' x 105 Pa 273 + 273 + Vf Vf Again we see that the volume Vf cancels out of the equation. °C K °℃ K = x 105 Pa.A bicycle tire has a pressure of 6.80 ✕ 105 N/m2 at a temperature of 19.0°C and contains 2.30 L of gas. What will its pressure be (in Pa) if you let out an amount of air that has a volume of 120 cm3 at atmospheric pressure? Assume tire temperature and volume remain constant. _________PaIn everyday experience, the measures of temperature most often used are Fahrenheit F and Celsius C. Recall that the relationship between them is given by the following formula. F = 1.8C + 32 Physicists and chemists often use the Kelvin temperature scale. You can get kelvins K from degrees Celsius by using the following formula. K = C + 273.15 (a) Calculate that value.K(25) = (b) Find a formula expressing the temperature C in degrees Celsius as a function of the temperature K in kelvins. C = (c) Find a formula expressing the temperature F in degrees Fahrenheit as a function of the temperature K in kelvins. F = (d) What is the temperature in degrees Fahrenheit of an object that is 272 kelvins?
- The gauge pressure in your car tires is 3.00 ✕ 105 N/m2 at a temperature of 35.0°C when you drive it onto a ship in Los Angeles to be sent to Alaska. What is their gauge pressure (in atm) later, when their temperature has dropped to −42.0°C? Assume the tires have not gained or lost any air. ____atm??A certain amount of gas at 25.0°C and at a pressure of 0.650 atm is contained in a glass vessel. Suppose that the vessel can withstand a pressure of 2.00 atm. How high can you raise the temperature of the gas without bursting the vessel? In other words, at what temperature will the glass vessel shatter, in degrees Celsius.A car tire has a gauge pressure of 205,749 Pa, volume of 3 L, and temperature of 7°C. After several hours of driving, the temperature of the air increases by 17C° and 11% of the gas leaks out due to a nail stuck in the tread. Calculate the gauge pressure of the tire in psi at this time if the ambient atmospheric pressure is 1.00 x 105 Pa. Neglect any volume change of the tire. (1000 L = 1 m³; 1 psi = 6895 Pa) (Be careful with units!) Pgauge psi