A car tire has a gauge pressure of 205,749 Pa, volume of 3 L, and temperature of 7°C. After several hours of driving, the temperature of the air increases by 17C° and 11% of the gas leaks out due to a nail stuck in the tread. Calculate the gauge pressure of the tire in psi at this time if the ambient atmospheric pressure is 1.00 x 105 Pa. Neglect any volume change of the tire. (1000 L = 1 m³; 1 psi = 6895 Pa) (Be careful with units!) Pgauge = psi
A car tire has a gauge pressure of 205,749 Pa, volume of 3 L, and temperature of 7°C. After several hours of driving, the temperature of the air increases by 17C° and 11% of the gas leaks out due to a nail stuck in the tread. Calculate the gauge pressure of the tire in psi at this time if the ambient atmospheric pressure is 1.00 x 105 Pa. Neglect any volume change of the tire. (1000 L = 1 m³; 1 psi = 6895 Pa) (Be careful with units!) Pgauge = psi
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![A car tire has a gauge pressure of 205,749 Pa, volume of 3 L, and temperature of
7°C. After several hours of driving, the temperature of the air increases by 17C° and
11% of the gas leaks out due to a nail stuck in the tread. Calculate the gauge
pressure of the tire in psi at this time if the ambient atmospheric pressure is 1.00 x
105 Pa. Neglect any volume change of the tire. (1000 L = 1 m³; 1 psi = 6895 Pa) (Be
careful with units!)
Pgauge
psi](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4941216-30bc-4530-82ab-758980652a1a%2Ffa0d06a9-574b-4fab-a644-9998e5c72a70%2Fod7j06r_processed.png&w=3840&q=75)
Transcribed Image Text:A car tire has a gauge pressure of 205,749 Pa, volume of 3 L, and temperature of
7°C. After several hours of driving, the temperature of the air increases by 17C° and
11% of the gas leaks out due to a nail stuck in the tread. Calculate the gauge
pressure of the tire in psi at this time if the ambient atmospheric pressure is 1.00 x
105 Pa. Neglect any volume change of the tire. (1000 L = 1 m³; 1 psi = 6895 Pa) (Be
careful with units!)
Pgauge
psi
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