An ordinary glass is filled to the brim with 250.0 mL of water, and both the glass and thewater are at 100.0°C. If the temperature of both the glass and the water is decreased to20.0°C, then answer the following. (a) What is the volume of the water? (b) What volumewill the glass hold? (c) Will water spill out or can you add more water to the glass? (d) Howmuch water either spilled out or can be added to the glass? Given that: Oglass = 9.00 x 10-6 1/Kand ẞwater = 210 × 10-6 1/K.

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Answered: An ordinary glass is filled to the brim…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A piece of copper tubing used in plumbing has a length of 54.0 cm Question 1. and an inner diameter of 1.25 cm at 22.0°C. When hot water at 95.0°C flows through the tube, what are (a) the tube's new length and (b) the change in its cross-sectional area? (c) if the density of copper is 8.92 x 103 kg/m³ at 22.0°C, find its density at 95.0°C
1. A bicycle pump inflates a tire of volume 565 mL until the gauge pressure is 6.47 bar at a temperature of 21.7°C. (Note: the volume of the tire before and after it is "inflated" is 565 mL. Initially, the tire contains air at ambient atmospheric pressure.) (a) If the barometric pressure is 1.01 bar, what is the absolute pressure in the tire? (b) (c) How many moles of air does the tire contain? What volume of air at 1.01 bar and 21.7°C did the pump transfer?
Step 1 (a) The ideal-gas equation describes each condition of the air in the tire. We will set up ratios in order to describe these changes. Dividing the equations PV = nRT in the initial and final states, we have PfVf Tf P¡Vi Ti Solving for the final pressure in the tire, gives Pf = = = which gives I Tf P(V)() P₁ Vf T₁ = (1.013 x 105 Pa) x 105 Pa. Note that the volume V¡ cancels out of the equation. = Vf Po = Pr (V ( ) ( ) Pd Pf Vi V₁ Step 2 (b) After the car is driven, the temperature and volume of air in the tire have changed. Let Td be the temperature and Vd be the volume of air in the tire. We have PdVd Td PfVf Tf' x 105 Pa 273 + 273 + Vf Vf Again we see that the volume Vf cancels out of the equation. °C K °℃ K = x 105 Pa.
A cylindrical glass flask with a diameter of 8 cm and the height of 20 cm is fully filled with water at 20°C. When the temperature of the water (and consequently the inner surface of the flask) is raised to 100° C, determine the volume of the water that overflows? HINT 1: Don't forget to calculate the initial volume of the water and flask HINT 2: The volume expansion coefficient for ordinary glass and water can be found in the table of Week 4 (Slide #20). HINT 3: Calculate the volume expansions for both water and the flask HINT 4: The difference between the final volume of water and the final volume of the flask is the amount of overflow. PLEASE UPLOAD YOUR HANDWRITTEN SOLUTION BY CLICKING ON THE "ADD A FILE" BUTTON.
The absolute pressure in your car tires is 3.7 × 105 Pa at a temperature of 35.0°C when you drive it onto a ferry boat to Alaska a. What is the absolute pressure of the tires, in pascals, later when the temperature has dropped to -40.0°C? Assume the volume of each tire does not change.
A bicycle tire has a pressure of 6.80 ✕ 105 N/m2 at a temperature of 19.0°C and contains 2.30 L of gas. What will its pressure be (in Pa) if you let out an amount of air that has a volume of 120 cm3 at atmospheric pressure? Assume tire temperature and volume remain constant. _________Pa
A runner weighs 663 N and 71% of this weight is water. (a) How many moles of water are in the runner's body? (b) How many water molecules (H2O) are there?
The gauge pressure in your car tires is 2.55 × 105 Pa at a temperature of 35.0°C when you drive it onto a ferry boat to Alaska. What is the gauge pressure of the tires, in pascals, later when the temperature has dropped to -40.0°C? Assume the volume of each tire does not change.
A machinist wishes to insert an iron rod with a diameter of 9 mm into a hole with a diameter of 8.998 mm. By how much would the machinist have to lower the temperature (in Celsius) of the rod to make it fit in the hole?
A hot air balloon uses the principle of buoyancy to create lift. By making the air inside the balloon less dense then the surrounding air, the balloon is able to lift objects many times its own weight. A large hot air balloon has a maximum balloon volume of 2090 m3. a. If the air temperature in the balloon is 54 °C, how much additional mass, in kilograms, can the balloon lift? Assume the molar mass of air is 28.97 g/mol, the air density is 1.20 kg/m3, and the air pressure is 1 atm.
Large helium-filled balloons are used to lift scientific equipment to high altitudes. (a)What is the pressure inside such a balloon (in atm) if it starts out at sea level with a temperature of 24.8°C and rises to an altitude where its volume is sixteen times the original volume and its temperature is −41.7°C? (Enter your answer to at least 3 decimal places) _______________ atm (b)What is the gauge pressure? (Enter your answer in atm and to at least 3 decimal places. Assume atmospheric pressure is constant.) ________________ atm

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