A beam of light fell on a polished plane of mica where it made an angle of (31.25° ) with the perpendicular to the flat surface, so if you know that the beam consists of two wavelengths, the first is (2 =404.7m ) and its refractive index in mica is equal to (1.4697 ) and the second is (1 =508.6m )and its refractive index in mica is equal to (1.4697 ), mathematically find the angle between the two refracted rays, if you know that the refractive index of air is equal to (1.0003 ).

A beam of light fell on a polished plane of mica where it made an angle of (31.25° ) with the perpendicular to the flat surface, so if you know that the beam consists of two wavelengths, the first is (2 =404.7m ) and its refractive index in mica is equal to (1.4697 ) and the second is (1 =508.6m )and its refractive index in mica is equal to (1.4697 ), mathematically find the angle between the two refracted rays, if you know that the refractive index of air is equal to (1.0003 ).

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Reflection And Refraction Of Light

Section: Chapter Questions

Problem 16P

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A ray of light strikes the midpoint of one face of an equiangular (60°–60°–60°) glass prism (n = 1.5) at an angle of incidence of 31.6°. (a) Trace the path of the light ray through the glass, and find the angles of incidence and refraction at each surface.First surface: ?incidence = ° ?refraction = ° Second surface: ?incidence = ° ?refraction = ° (b) If a small fraction of light is also reflected at each surface, find the angles of reflection at the surfaces. ?reflection = ° (first surface) ?reflection = ° (second surface)
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A ray of monochromatic light is incident on the face of a prism in the shape of an equilateral triangle (that is, the apex angle of the prism is 60.0°). The incidence angle of the light ray is 76.6°. The prism is made of a transparent material with an index of refraction of 1.516 (at the light ray's wavelength). (a) Calculate the angle of refraction at the first surface (in degrees). (Round your answer to at least one decimal place.) ° (b) Calculate the angle of incidence at the second surface (in degrees). (Round your answer to at least one decimal place.) ° (c) Calculate the angle of refraction at the second surface (in degrees). (Round your answer to at least one decimal place.) ° (d) Calculate the angle between the incident and emerging rays (in degrees). (Round your answer to at least one decimal place.) °
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Refractive Index (n) is a ratio of the speed of light in a vacuum to the speed of light in materials such as glass, water, plastic, etc. Using Snell's Law, and given an air to glass interface with and angle of incidence of 15 degrees, what will be the angle of refractance R if the refractive index of the glass is 1.5 ? Snell's Law: n; (sin I) = n, (sin R) So, Sin R = n; (sin I) / n And, R = arcsin (n; (sin I) / n,) For each angle I, find angle R: 5. I=0, R = 6. I=45, R = 7. I= 60, R = 8. I = 75, R = = arcsin (1(.259)/1.5) = arcsin (.172) = 9.9 degrees Wavelength in Air- Light- Angle of Light -Wavelength in Glass Normal 90° R Air nj-1 Glass
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A ray of white light traveling through air enters a triangular prism that has an index of refraction of 1.512 for the red end of the spectrum and 1.539 for the violet end and an apex angle of 64.1 degrees. If the ray has an angle of incidence of 49.8 degrees with respect to the normal of the interface boundary, what is the angular separation between the red and violet ends of the spectrum upon exiting the prism? Measure this in degrees to 2 decimal places.