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A beam has the singly symmetrical thin-walled cross section shown in Fig. P.10.7. Each wall of the section is flat and has the same length, a, and thickness, 1. Determine the shear flow distribution round the section due to a vertical shear load, S, applied through the shear centre and find the distance of the shear centre from the point C. Ans. qAB =-3S,(2as^-s/2)/16a² sin a qBC =-3S,(3/2+sg/a-s/2a²)/16a sin a S.C. is 5a cos a/8 from C.

A beam has the singly symmetrical thin-walled cross section shown in Fig. P.10.7. Each wall of the section is flat and has the same length, a, and thickness, 1. Determine the shear flow distribution round the section due to a vertical shear load, S, applied through the shear centre and find the distance of the shear centre from the point C. Ans. qAB =-3S,(2as^-s/2)/16a² sin a qBC =-3S,(3/2+sg/a-s/2a²)/16a sin a S.C. is 5a cos a/8 from C.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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7 A beam has the singly symmetrical thin-walled cross section shown in Fig. P.10.7. Each wall of the section is flat and has the same length, a, and thickness, t. Determine the shear flow distribution round the section due to a vertical shear load, S, applied through the shear centre and find the distance of the shear centre from the point C. Ans. qAB = -3S,(2asa-s/2)/16a² sin a qBC =-3S,(3/2+ $g/a=s%/2a²)/16a sin a S.C. is 5a cos a/8 from C.
Transcribed Image Text:7 A beam has the singly symmetrical thin-walled cross section shown in Fig. P.10.7. Each wall of the section is flat and has the same length, a, and thickness, t. Determine the shear flow distribution round the section due to a vertical shear load, S, applied through the shear centre and find the distance of the shear centre from the point C. Ans. qAB = -3S,(2asa-s/2)/16a² sin a qBC =-3S,(3/2+ $g/a=s%/2a²)/16a sin a S.C. is 5a cos a/8 from C.
a A В 2a] SB a S a D< 2a
Transcribed Image Text:a A В 2a] SB a S a D< 2a
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