**Ballistic Pendulum Experiment***A ballistic pendulum consists of a 3.9-kg wooden block originally at rest, with θ = 0°. When a 2-g bullet strikes and becomes embedded in it, it is observed that the block swings upward to a maximum angle of θ = 6°. (Figure 1)***Figure Description:**The figure illustrates a ballistic pendulum setup. The pendulum consists of a wooden block suspended by two ropes, each 1.25 meters in length. Initially, the block is at an angle θ = 0°, indicating it is hanging straight down. A bullet is shown approaching the block, pointing towards where it strikes and becomes embedded. As a result, the block swings upward, reaching a maximum angle of θ = 6°.**Part A***Task: Estimate the speed of the bullet.*- **Instruction:** Express your answer to three significant figures and include the appropriate units.**Input Field:**\( v_B = \) [Value] [Units]- **Buttons Available:** Formatting options, submit, request answer, and feedback options.This experiment aims to calculate the initial speed of the bullet using principles of conservation of momentum and energy, by analyzing the change in angle of the pendulum after the collision.

Block mass M= 3.9 kgBullet mass m= 2 g=0.002 kgAngle =60

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