A ball of mass 200 g is released from rest at a height of 2.50 m above the floor and it rebounds straight up to a height of 0.900 m. If the contact time with the floor was 0.0950 seconds, what was the average force the floor exerted on the ball? I have delta P= 2.2412 kg m/s I used the equation Fnet = delta P / delta T I got the answer 23.6N, which was labeled incorrect. Where am I going wrong?

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