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A ball is launched from the top of an 24.8 m tall building at an angle = 26.0° above horizontal with a speed of 2.85 m/s. What is the ball's horizontal distance (in m) from the building at the time it reaches the ground? Use g = 9.81 m/s?). (These are my steps but I don’t know what to do next. The outcome should be 6.1. I did 2.13*2.562 and got 5.46. Don’t know what I did wrong)

A ball is launched from the top of an 24.8 m tall building at an angle = 26.0° above horizontal with a speed of 2.85 m/s. What is the ball's horizontal distance (in m) from the building at the time it reaches the ground? Use g = 9.81 m/s?). (These are my steps but I don’t know what to do next. The outcome should be 6.1. I did 2.13*2.562 and got 5.46. Don’t know what I did wrong)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A ball is launched from the top of an 24.8 m tall building at an angle = 26.0° above horizontal with a speed of 2.85 m/s. What is the ball's horizontal distance (in m) from the building at the time it reaches the ground? Use g = 9.81 m/s?). (These are my steps but I don’t know what to do next. The outcome should be 6.1. I did 2.13*2.562 and got 5.46. Don’t know what I did wrong)
2.85 Cos (26) = 2.562 2.85 Sin (26) −1.2494 2 24.8- (1.2494)T + ½ (98|) 1 4.912 + 1.2494_T-24.8 + >o 4.912 + 1.2494 + - 24. 8 = 0 Use quadratic lavation out come from equestion. + - - 2, 3 8 12 : 2.13
Transcribed Image Text:2.85 Cos (26) = 2.562 2.85 Sin (26) −1.2494 2 24.8- (1.2494)T + ½ (98|) 1 4.912 + 1.2494_T-24.8 + >o 4.912 + 1.2494 + - 24. 8 = 0 Use quadratic lavation out come from equestion. + - - 2, 3 8 12 : 2.13
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