**Problem Description:**You tossed out a ball from a building at a height of 50.0 meters above the ground with an initial velocity of 9.00 m/s and an angle of 25° to the horizontal. It strikes the ground after 5.00 seconds. With the positive x-direction chosen to be out of the window, how far horizontally from the base of the building does the ball strike the ground?**Solution Approach:**To find the horizontal distance from the base of the building where the ball strikes the ground, we need to analyze the projectile motion of the ball:1. **Initial Velocity Components:** - Horizontal component (vx): \( v_0 \cdot \cos(\theta) \) - Vertical component (vy): \( v_0 \cdot \sin(\theta) \) Where \( v_0 = 9.00 \, \text{m/s} \) and \( \theta = 25^\circ \).2. **Horizontal Distance Calculation:** - The horizontal distance (x) can be calculated using the formula: \[ x = v_x \cdot t \] - Since there is no acceleration in the horizontal direction, the horizontal component of velocity remains constant.3. **Substituting the Values:** - Calculate \( v_x = 9.00 \cdot \cos(25^\circ) \) - The time of flight (t) is given as 5.00 seconds.4. **Final Calculation:** - Substitute these values into the equation for x to find the horizontal distance.This approach gives a step-by-step explanation of how to solve the problem of determining the horizontal range of the projectile.

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Description: **Problem Description:**You tossed out a ball from a building at a height of 50.0 meters above the ground with an initial velocity of 9.00 m/s and an angle of 25° to the horizontal. It strikes the ground after 5.00 seconds. With the positive x-direc

Given:- The height of the ball from the ground h = 50 m initial velocity vi = 9.0 m/s and angle of…

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You tossed out a ball from a building at a height of 50.0 meter abov of 9.00 m/s and angle of 25° to the horizontal. It strikes the ground positive x-direction chosen to be out of the window, how far horizo does the ball strike the ground?

You tossed out a ball from a building at a height of 50.0 meter abov of 9.00 m/s and angle of 25° to the horizontal. It strikes the ground positive x-direction chosen to be out of the window, how far horizo does the ball strike the ground?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Projectile Motion

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**Problem Description:**

You tossed out a ball from a building at a height of 50.0 meters above the ground with an initial velocity of 9.00 m/s and an angle of 25° to the horizontal. It strikes the ground after 5.00 seconds. With the positive x-direction chosen to be out of the window, how far horizontally from the base of the building does the ball strike the ground?

**Solution Approach:**

To find the horizontal distance from the base of the building where the ball strikes the ground, we need to analyze the projectile motion of the ball:

1. **Initial Velocity Components:**
- Horizontal component (vx): \( v_0 \cdot \cos(\theta) \)
- Vertical component (vy): \( v_0 \cdot \sin(\theta) \)

Where \( v_0 = 9.00 \, \text{m/s} \) and \( \theta = 25^\circ \).

2. **Horizontal Distance Calculation:**
- The horizontal distance (x) can be calculated using the formula:
\[
x = v_x \cdot t
\]
- Since there is no acceleration in the horizontal direction, the horizontal component of velocity remains constant.

3. **Substituting the Values:**
- Calculate \( v_x = 9.00 \cdot \cos(25^\circ) \)
- The time of flight (t) is given as 5.00 seconds.

4. **Final Calculation:**
- Substitute these values into the equation for x to find the horizontal distance.

This approach gives a step-by-step explanation of how to solve the problem of determining the horizontal range of the projectile.

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