Using the same initial velocity (3.30 m/s), find: a) the time taken for the ball to reach a horizontal distance of x = 0.35 m, using the appropriate kinematical equations. b) the height above the launch point, i.e. y(t) of the ball be at when the horizontal distance is x(t) = 0.35 m. Remember, the initial velocity now has x and y-components.

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Chapter2: Vectors
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x(t), y(t)
Yo
Figure a: Projectile launched at an angle 0 above the surface of a table.
Using the same initial velocity (3.30 m/s), find:
a) the time taken for the ball to reach a horizontal distance of x =
0.35 m, using the appropriate kinematical equations.
b) the height above the launch point, i.e. y(t) of the ball be at when
the horizontal distance is x(t) = 0.35 m.
Remember, the initial velocity now has x and y-components.
Vxo = V, cos(0)
Vyo = V, sin(0)
Transcribed Image Text:x(t), y(t) Yo Figure a: Projectile launched at an angle 0 above the surface of a table. Using the same initial velocity (3.30 m/s), find: a) the time taken for the ball to reach a horizontal distance of x = 0.35 m, using the appropriate kinematical equations. b) the height above the launch point, i.e. y(t) of the ball be at when the horizontal distance is x(t) = 0.35 m. Remember, the initial velocity now has x and y-components. Vxo = V, cos(0) Vyo = V, sin(0)
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