a bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one back in the bag, what is the probability that the first ball will be green and the second will be red?

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Q: 3.

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Q: 4 + 2.4 + 1.44 + 0.864 + ..

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Q: his

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Q: Which is the correct option? a.  0.9949 b. 0.9696  c. 0.9996  d. 0.0801

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