Lee is a teacher at a local high school who wanted to assess whether or not dogs physically resemble their owners enough for people to be able to correctly match a dog to their owner better than if just guessing. Lee, who is also a dog owner, showed pictures of two dogs to her class of 16 students. One photo was of the teacher's dog (Yoda) and the other photo was of a dog the teacher had never met. The students were asked to guess which dog was actually the teacher's. If dogs do not physically resemble their owners, the students would get a correct match with probability 0.50. It turned out that 14 of the 16 students correctly picked out the teacher's dog. Does it appear that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just guessing? The hypotheses to be tested are Ho: p = 0.50 versus Ha: p > 0.50, where the parameter p represents the population proportion of all people who can correctly match a dog to their owner (out of two options).
Lee is a teacher at a local high school who wanted to assess whether or not dogs physically resemble their owners enough for people to be able to correctly match a dog to their owner better than if just guessing. Lee, who is also a dog owner, showed pictures of two dogs to her class of 16 students. One photo was of the teacher's dog (Yoda) and the other photo was of a dog the teacher had never met. The students were asked to guess which dog was actually the teacher's. If dogs do not physically resemble their owners, the students would get a correct match with probability 0.50. It turned out that 14 of the 16 students correctly picked out the teacher's dog. Does it appear that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just guessing? The hypotheses to be tested are Ho: p = 0.50 versus Ha: p > 0.50, where the parameter p represents the population proportion of all people who can correctly match a dog to their owner (out of two options).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Read the following prompt and complete the subquestions 3.a, 3.b, and 3.c
Transcribed Image Text:3.b
If the null hypothesis is true, what is the distribution of the test statistic (that is, which distibution should be used to find the p-value)?
Bin(n = 16, p = 0.50) distribution
Bin(n = 16, p = 0.875) distribution
N(0.50, 0.125) distribution
N(0,1) distribution
3.c
What is the corresponding p-value for this test?
Challenge: compute it yourself, going through all the steps (for exam practice), and then compare it to the possible answers.
0.00135
0.50
0.00209
0.001831
0.000244
0.000015
Transcribed Image Text:Question 3 Background :
Pets and Their Owners
Lee is a teacher at a local high school who wanted to assess whether or not dogs physically resemble their owners enough for people to be able to
correctly match a dog to their owner better than if just guessing. Lee, who is also a dog owner, showed pictures of two dogs to her class of 16 students.
One photo was of the teacher's dog (Yoda) and the other photo was of a dog the teacher had never met. The students were asked to guess which
dog was actually the teacher's. If dogs do not physically resemble their owners, the students would get a correct match with probability 0.50. It turned
out that 14 of the 16 students correctly picked out the teacher's dog.
Does it appear that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just
guessing? The hypotheses to be tested are Ho:P
who can correctly match a dog to their owner (out of two options).
0.50 versus Ha: p > 0.50, where the parameter p represents the population proportion of all people
Question 3 Subquestions
3.а
Noticing that the sample size is just 16, what is the observed value of the test statistic for testing the hypotheses for this study?
3.00
14/16 = 0.875
87.5%
14
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