a b с PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd Potential = An external voltage source is needed. The reaction will proceed spontaneously. V ZnZn²+ (0.0560 M)||T1³+ (9.22 × 10-² M), Tl¹ (0.0230 M)| Pt Potential = Potential = V Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ 4 M)||Ni²+ (0.0940 M) Ni V
a b с PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd Potential = An external voltage source is needed. The reaction will proceed spontaneously. V ZnZn²+ (0.0560 M)||T1³+ (9.22 × 10-² M), Tl¹ (0.0230 M)| Pt Potential = Potential = V Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ 4 M)||Ni²+ (0.0940 M) Ni V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![d
PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd
f
Potential =
b Zn|Zn²+ (0.0560 M)||T1³+ (9.22 × 10−² M), T1¹ (0.0230 M)| Pt
An external voltage source is needed.
The reaction will proceed spontaneously.
Potential =
Potential =
V
Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ (0.0940 M)| Ni
Potential =
V
Pb|Pb 1₂ (sat 'd), I¯ (0.0440 M)||Hg²+ (6.90 × 10-³
I™
Potential =
V
Potential =
V
Pt, H₂ (2.70 atm) | NH3 (0.730 M), NH4+ (0.170 M)|| SHE
³ M) | Hg
Pt/TiO²+ (0.0610 M), Ti³+ (0.00510 M), H+ (1.70 × 10-² M)||
VO²+ (0.1400 M), V³+ (0.0440 M), H+ (0.0290 M)|Pt
V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3180ecf1-e273-42d3-b0c6-3dff30b2341e%2Fa9782300-906c-4644-9d0e-bdef658856c1%2Fdj8mixr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:d
PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd
f
Potential =
b Zn|Zn²+ (0.0560 M)||T1³+ (9.22 × 10−² M), T1¹ (0.0230 M)| Pt
An external voltage source is needed.
The reaction will proceed spontaneously.
Potential =
Potential =
V
Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ (0.0940 M)| Ni
Potential =
V
Pb|Pb 1₂ (sat 'd), I¯ (0.0440 M)||Hg²+ (6.90 × 10-³
I™
Potential =
V
Potential =
V
Pt, H₂ (2.70 atm) | NH3 (0.730 M), NH4+ (0.170 M)|| SHE
³ M) | Hg
Pt/TiO²+ (0.0610 M), Ti³+ (0.00510 M), H+ (1.70 × 10-² M)||
VO²+ (0.1400 M), V³+ (0.0440 M), H+ (0.0290 M)|Pt
V
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