a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation C,H5OH(g) – CH3CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time, and the following data was obtained: Time (s) | P(C2H,ОН) (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing. Rate = k Rate = k[CH3CHO][H,j² Rate = k[C2H5OH][CH;CHO][H2] O Rate = k[C2H5OH]
a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation C,H5OH(g) – CH3CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time, and the following data was obtained: Time (s) | P(C2H,ОН) (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing. Rate = k Rate = k[CH3CHO][H,j² Rate = k[C2H5OH][CH;CHO][H2] O Rate = k[C2H5OH]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation
C,H5OH(g) –
CH3CHO(g) + H2(g)
The pressure of C2H5OH was measured as a function of time, and the following data was obtained:
Time (s) | P(C2H,ОН) (torr)
250.
100.
237
200.
224
300.
211
400.
198
500.
185
Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures.
Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing.
Rate = k
Rate = k[CH3CHO][H,j²
Rate = k[C2H5OH][CH;CHO][H2]
O Rate = k[C2H5OH]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb417ffb6-eb7d-4466-b664-89f966a306a6%2Ff9600249-a749-41a3-a850-68f1b20cd2e6%2Fmmqdpdn.png&w=3840&q=75)
Transcribed Image Text:a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation
C,H5OH(g) –
CH3CHO(g) + H2(g)
The pressure of C2H5OH was measured as a function of time, and the following data was obtained:
Time (s) | P(C2H,ОН) (torr)
250.
100.
237
200.
224
300.
211
400.
198
500.
185
Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures.
Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing.
Rate = k
Rate = k[CH3CHO][H,j²
Rate = k[C2H5OH][CH;CHO][H2]
O Rate = k[C2H5OH]
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