A air-filled capacitor with C = 3 F is charged to an initial voltage V = 13 V and disconnected from the voltage source. Find the final voltage after a dielectric of constant K = 5.41 is inserted between the plates.
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- The capacitor is charged to a voltage of 4.00 kv using a power source that is then removed. The gap between the plates is then filled by a dielectric layer. The charge on each plate stays constant at 2.50 kv despite the reduction in the potential difference between the plates. Calculate the initial capacitance value of the system.A professor designing a class demonstration connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.47 cm and a plate area of A = 25.0 cm². When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before after AV f (b) Determine the capacitance (in F) and potential difference (in V) after immersion. Cf= = = (c) Determine the change in energy (in nJ) of the capacitor. AU = nJ AV f (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before after…A parallel plate capacitor with plate separation do is charged by connecting it to a battery. The energy stored by the capacitor is Ug. The battery is then disconnected and the plate separation is changed to d1 = 0.7do. If U1 is the energy stored by the capacitor when the plate separation is di, what is the ratio U1/Uo? O (a) 0.7 O (b) 0.837 O (c) 0.49 O (d) 2.04 O (e) 1.43 O (f) 1.2
- The parallel plates in a capacitor, with a plate area of 6.70 cm2 and an air-filled separation of 2.60 mm, are charged by a 7.70 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.50 mm. Neglecting fringing, find (d) the work required to separate the plates.A certain capacitor has a capacitance of 4μF when its plates are separated by 0.2 mm of vacant space. A battery is used to charge the plate to a potential difference of 500 V and is then disconnected from the system. (a) What will be the potential difference across the plates if a sheet of mica 0.2 mm thick is inserted between the plates? (b) What will the capacitance be after the dielectric is inserted? (c) What is the permittivity of mica?An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = C
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