A) A timing circuit is shown in Figure 2A. For both transistors, KREn = 0.7V, KCERR = 0.2V and Br is large. The transistor Q1 has been OFF for a long time, while Q2 is saturated. At t = 0 a step input of 5V is applied to the base of Q1, which causes Q1 to saturate and turns Q2 OFF. i. Find the voltage at the base of Q2 just after the step input is applied, V32(0*). How long does it take before Q2 turns back on? ii. I VCC = 6V VA = 3V 2kN 2kΩ 50kΩ Vo 0.01 uF Q1 Q2 50kn VB2 Vstep Figure 2A

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.