Pag(A)a dedicated accumulator. All instructions and operands are stored in memory, and are of the same size,consisting of opcode and memory address. If no operand is needed, memory address is 0. The machinesinstructions are fetched from memory, the opcode is decoded, and then the instruction is executed.Assume that we have a computer with 200 opcodes and a memory address of 10 bits. ItThis computer has a dedicated accumulator AC, program counter PC, memory address register MAmemory buffer register MBR, an instruction register IR, and an arithmetic logic unit.1.What is the size of opcode in bits?bits2. What will be the largest number of words in the memory (write in decimal)?words3. What is the size of the memory word in bits?bits4. What are the sizes of the following registers in bits?MAR:PC:AC:MBR:

i have answer this question in step 2.

Answered: (A) a dedicated accumulator. All…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Please answer all the following questions. 1. In a hypothetical computer, the processor has four registers: an 8-bit Program Counter (PC), a 16-bit Accumulator (AC), a 16-bit Counter (CTR), and a 12-bit Pointer (PTR). The memory is divided into words each of which is 16-bit long. Each word can hold either an instruction or a piece of data. For each instruction X, the four most significant bits (denoted by X15-12) represent an opcode. The rest of the instruction (denoted by X11-0) can be either an address or a value of an operand. The table below explains some of the instructions supported by the processor. Opcode (binary) 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 Operation Load AC from a memory location whose address is X11-0. Store AC into a memory location whose address is X11-0. Add to AC the contents of a memory location whose address is the value of PTR. The result is saved to AC. 1100 Subtract from AC the contents of a memory location whose address is the value…
1.Address of the opcode; 5CD 2.Address of the operand for the operation; 5DE 3.None of these 4.Address of the operand for the operation; 5CD
The most time - consuming operation in a computer is: O A. Register access O B. The execution phase of a register reference instruction Memory access. O D. The decoding phase of an instruction cycle
A computer with a 32-bit 3.5 gigahertz scalar non- pipelined CPU needs to invert the colors of a 150 KB bitmap image file located in the RAM. To do this, each bit of the image must be complemented (Os are converted to 1s and vice-versa). Assume every instruction undergoes the following stages and each stage uses one CPU clock cycle: • Fetch • Decode • Read from memory • Execute • Write to memory Instructions: For this assignment, you must calculate how much time the computer will need to invert the image with a single-core and a dual core CPU. Show and explain your calculations and assumptions in a short paper and answer the following questions: • Will there be any parallel slowdown? Why or why not? Length: 2-3 page explanatory paper
Choose an answer and write the procedureIn a microcontroller, the interior of the memory that goes from 0x200 to 0x21FF has been reserved for the program code.What is the maximum size that a program code can have?A) 256B) 512C) 1024D)128
In the von Neumman model, the PC is used to store: A. The data to use in executing the instruction B. The instruction to be executed C. The location of the next instruction to be executed D. The program and the data not currently being used in execution
A microoperation and a machine instruction seem to be interchangeable terms.
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 150 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address, similar to Marie). Each instruction is stored in one word of memory. a) How many bits are needed for the opcode? b) How many bits are left for the address part of the instruction? c) What is the maximum allowable size for memory?

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