a) A college principal decides to consult the students about a proposed change in the time oflectures. She finds that out of a random sample of 80 students, 57 are in favour of the change.Calculate a 95% confidence interval for the proportion of students who are not infavour of the change.i.State the effect on the width of such a confidence larval when the confidence level isincreased.ii.

Given that Total student are 80 of which 57 are favoure of change then 23 are not favoure Proportion…

Answered: a) A college principal decides to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a sample of 7 observations, the values are 17, 11, 12, 13, 14, 15. 16. Find the 95% confidence interval for the population mean. O A. (5.00, 9.00) O B. (4.00, 8.00) OC (12.00, 16.00) OD.(11.00, 15.00)
CNN is conducting a poll, and wants to produce a 90% confidence interval for the proportion of all New York residents who favor legalizing recreational marijuana. Of the 602 randomly selected New Yorkers surveyed, 394 were in favor of the initiative. a. With 90% confidence, the proportion of New York residents who favor legalizing recreational marijuana is between BLANK and BLANK. b. Suppose that we survey 602 randomly selected Americans many times, and calculate a confidence interval for each group. About Blank . percent of these confidence intervals will contain the true population proportion of New Yorkers who favor legalizing recreational marijuana, and about BLANK percent will not contain the true population proportion.
If the number of smokers in a sample of 40 students selected from university A is 14 and the number of smokers in a sample of 380 students selected from university B is 84. Then the 99% confidence interval for the difference between proportions of smokers in the two universities (PB- PA) is closest to O a. (-0.1450,-0.1130) O b. (-0.3310,0.0729) O c. None of these o d. (-0.3110,0.0534) e. (-0.1430,-0.1150)
A consumer group reports that a 90% confidence interval for the mean fat content of chicken nuggets from a fast-food restaurant is (14, 18). What is the mean fat content for the sample of 30 chicken nuggets or the point estimate that help make this confidence interval? A. 32 B. 16 C. 2
A researcher surveyed college students in the United States on the typical amount of time each day that they spend interacting with different types of media (television, social media, Internet-connected devices, game consoles, etc.) The researcher found that the mean amount of time that college students spent watching television each day is 135 minutes with a 95% confidence interval of (105, 165). a. State the conclusion the researcher can make from this confidence interval. b. What is the margin of error for the confidence interval?
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
A beverage company would like to determine if their drink is preferred to a rival company’s drink. They perform an experiment with 150 randomly selected individuals and have them taste test the two different drinks in a controlled environment so that each person's preference is independent of others. A 90% confidence interval for the proportion preferring their drink is (0.453, 0.587). Which of the following is the correct interpretation of this confidence interval? 90% of all consumers prefer this beverage company’s drink to their rival’s between 45.3% and 58.7% of the time. We’re 90% confident that between 45.3% and 58.7% of all consumers would prefer this beverage company’s drink to their rival’s drink. We’re 90% confident that there’s a 45.3% to 58.7% chance that a randomly selected person would prefer this beverage company’s drink to their rival’s drink. We’re 90% confident that the proportion of people in the sample who prefer this beverage company’s drink over their…
A study is conducted by a physical therapist to determine whether there is a difference in the proportion of men and women in the U.S. that participate in regular sustained physical activity. It is found that 22% of menout of 550 and 19.5% of women out of 450 participated in regular sustained physical activity. Construct a 90% confidence interval for the difference in proportions of men and women that participate in regular sustained and state your conclusion.
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