(a) A ball is attached to a string of length L = 20.5 cm and suspended from the ceiling, as shown in the figure. A uniform electric field points to the right in the figure. When e = 13.0°, the ball is in equilibrium. Find the net charge on the ball (in µC). E = 1.00 × 10³ N/C m = 2.00 g 84.87 opposite It seems that you swapped sine and cosine in your calculation. Remember that sin(0) = hypotenuse (b) What If? If the electric field is suddenly turned off, what is the speed of the ball at the bottom of its swing (in m/s)? 0.35 Use energy conservation and solve your resulting equation for the speed v. m/s

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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(a) A ball is attached to a string of length L
20.5 cm and suspended from the ceiling, as shown in the figure. A uniform electric field points to the right in the figure. When 0 =
13.0°, the ball is in
%D
equilibrium. Find the net charge on the ball (in µC).
E = 1.00 × 10³ N/C
m = 2.00 g
84.87
opposite
It seems that you swapped sine and cosine in your calculation. Remember that sin(0)
hypotenuse
(b) What If? If the electric field is suddenly turned off, what is the speed of the ball at the bottom of its swing (in m/s)?
0.35
Use energy conservation and solve your resulting equation for the speed v. m/s
Transcribed Image Text:(a) A ball is attached to a string of length L 20.5 cm and suspended from the ceiling, as shown in the figure. A uniform electric field points to the right in the figure. When 0 = 13.0°, the ball is in %D equilibrium. Find the net charge on the ball (in µC). E = 1.00 × 10³ N/C m = 2.00 g 84.87 opposite It seems that you swapped sine and cosine in your calculation. Remember that sin(0) hypotenuse (b) What If? If the electric field is suddenly turned off, what is the speed of the ball at the bottom of its swing (in m/s)? 0.35 Use energy conservation and solve your resulting equation for the speed v. m/s
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