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a) a) A thin rod of mass M = 0.5 kg and length L= 8 m is attached to a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iday = mr?. Calculate the moment of inertia relative to the point of rotation Q immediately after the collision. Hint: find r for the clay ball (distance from the point of rotation to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md², find d for the rod (distance from the point of rotation Q to the center of mass of the rod). b) CMod b) A thin rod of mass M = 0.5 kg and length L = 8 m is initially at rest on a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m =1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore lday = mr?. Calculate the moment of inertia relative to the center of mass of the system immediately after the collision. Hint: find the center of mass of the system, then find r for the clay ball (distance from the center of mass of the system to the object). Apply the parallel axis theorem for the rod Irod = IcM rod + Md?, find d for the rod (distance from the center of mass of the system to the center of mass of the rod).

a) a) A thin rod of mass M = 0.5 kg and length L= 8 m is attached to a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iday = mr?. Calculate the moment of inertia relative to the point of rotation Q immediately after the collision. Hint: find r for the clay ball (distance from the point of rotation to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md², find d for the rod (distance from the point of rotation Q to the center of mass of the rod). b) CMod b) A thin rod of mass M = 0.5 kg and length L = 8 m is initially at rest on a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m =1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore lday = mr?. Calculate the moment of inertia relative to the center of mass of the system immediately after the collision. Hint: find the center of mass of the system, then find r for the clay ball (distance from the center of mass of the system to the object). Apply the parallel axis theorem for the rod Irod = IcM rod + Md?, find d for the rod (distance from the center of mass of the system to the center of mass of the rod).

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a) a) A thin rod of mass M = 0.5 kg and length L= 8 m is attached to a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iday = mr?. Calculate the moment of inertia relative to the point of rotation Q immediately after the collision. Hint: find r for the clay ball (distance from the point of rotation to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md?, find d for the rod (distance from the point of rotation Q to the center of mass of the rod). b) CMod. b) A thin rod of mass M = 0.5 kg and length L = 8 m is initially at rest on a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iclay = mr2. Calculate the moment of inertia relative to the center of mass of the system immediately after the collision. Hint: find the center of mass of the system, then find r for the clay ball (distance from the center of mass of the system to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md², find d for the rod (distance from the center of mass of the system to the center of mass of the rod).
Transcribed Image Text:a) a) A thin rod of mass M = 0.5 kg and length L= 8 m is attached to a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iday = mr?. Calculate the moment of inertia relative to the point of rotation Q immediately after the collision. Hint: find r for the clay ball (distance from the point of rotation to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md?, find d for the rod (distance from the point of rotation Q to the center of mass of the rod). b) CMod. b) A thin rod of mass M = 0.5 kg and length L = 8 m is initially at rest on a frictionless table and is struck at a point L/4 from its CM (as shown) by a clay ball of mass m = 1 kg moving at some speed. The ball sticks to the rod and rotates after the collision. Consider the clay ball as a point object, therefore Iclay = mr2. Calculate the moment of inertia relative to the center of mass of the system immediately after the collision. Hint: find the center of mass of the system, then find r for the clay ball (distance from the center of mass of the system to the object). Apply the parallel axis theorem for the rod Irod = ICM rod + Md², find d for the rod (distance from the center of mass of the system to the center of mass of the rod).
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