A 70.0 mL solution of 0.550 M Pb(NO3)2 was mixed with 55.0 mL of 0.600 M Na3PO4, resulting in the reaction shown below: 3 Pb(NO3)2 (aq) + 2 Na3PO4 (aq) → Pb3(PO4)2 (s) + 6 NaNO3(aq) a) What are the molecular weights of Pb(NO3)2, Na3PO4, Pb3(PO4)2? Pb(NO3)2: Na3PO4: Pb3(PO4)2: b) Determine the theoretical amount of Pb3(PO4)2 (s) formed in grams. Mass: c) Determine the amount of unused reactant in grams. Mass: g/mol g/mol g/mol 8.0 g 80 g
A 70.0 mL solution of 0.550 M Pb(NO3)2 was mixed with 55.0 mL of 0.600 M Na3PO4, resulting in the reaction shown below: 3 Pb(NO3)2 (aq) + 2 Na3PO4 (aq) → Pb3(PO4)2 (s) + 6 NaNO3(aq) a) What are the molecular weights of Pb(NO3)2, Na3PO4, Pb3(PO4)2? Pb(NO3)2: Na3PO4: Pb3(PO4)2: b) Determine the theoretical amount of Pb3(PO4)2 (s) formed in grams. Mass: c) Determine the amount of unused reactant in grams. Mass: g/mol g/mol g/mol 8.0 g 80 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Reaction Problem Set**
**Problem Description:**
A 70.0 mL solution of 0.550 M Pb(NO₃)₂ was mixed with 55.0 mL of 0.600 M Na₃PO₄, resulting in the following chemical reaction:
\[ 3 \, \text{Pb(NO}_3\text{)}_2\, \text{(aq)} + 2 \, \text{Na}_3\text{PO}_4 \, \text{(aq)} \rightarrow \text{Pb}_3(\text{PO}_4)_2 \, \text{(s)} + 6 \, \text{NaNO}_3 \, \text{(aq)} \]
**Tasks:**
a) What are the molecular weights of Pb(NO₃)₂, Na₃PO₄, Pb₃(PO₄)₂?
- **Pb(NO₃)₂:**
g/mol
- **Na₃PO₄:**
g/mol
- **Pb₃(PO₄)₂:**
g/mol
b) Determine the theoretical amount of Pb₃(PO₄)₂ (s) formed in grams.
- **Mass:**
g
c) Determine the amount of unused reactant in grams.
- **Mass:**
g](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe21ad11-6e18-4b63-a679-8109648f0f0b%2Fc7ffa3f7-8cc9-4cbe-9f4a-f203d39b38c4%2F1ze9jds_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction Problem Set**
**Problem Description:**
A 70.0 mL solution of 0.550 M Pb(NO₃)₂ was mixed with 55.0 mL of 0.600 M Na₃PO₄, resulting in the following chemical reaction:
\[ 3 \, \text{Pb(NO}_3\text{)}_2\, \text{(aq)} + 2 \, \text{Na}_3\text{PO}_4 \, \text{(aq)} \rightarrow \text{Pb}_3(\text{PO}_4)_2 \, \text{(s)} + 6 \, \text{NaNO}_3 \, \text{(aq)} \]
**Tasks:**
a) What are the molecular weights of Pb(NO₃)₂, Na₃PO₄, Pb₃(PO₄)₂?
- **Pb(NO₃)₂:**
g/mol
- **Na₃PO₄:**
g/mol
- **Pb₃(PO₄)₂:**
g/mol
b) Determine the theoretical amount of Pb₃(PO₄)₂ (s) formed in grams.
- **Mass:**
g
c) Determine the amount of unused reactant in grams.
- **Mass:**
g
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