A 70.0 kg man jumping from a window lands in an elevated fire rescue net 11.0 m below the window. He momentarily stops when he has stretched the net by 1.50 m. Assuming that mechanical energy is conserved during this process and that the net functions like an ideal spring, find the elastic potential energy of the net when it is stretched by 1.50 m.

Q: A 30.0° frictionless inclined plane has a spring at the bottom. A block of mass m = 5.00 kg starts…

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Q: Is the force involved in the following situations conservative or nonconservative? Please justify.…

A: Required : If the forces involved are conservative or non conservative.

Q: A block of mass 2.80 kg is placed against a horizontal spring of constant k = 745 N/m and pushed so…

A: (a) The elastic potential energy of the block-spring system is as follows: PE=12kx2PE=12745…

Q: What is the difference in maximum stored energy between the sprinters and the non-athletes

A: Given, Spring constant , k = 33 N/mm stretch in sprinter , x1 = 44mm = 0.044 m stretch in sprinter ,…

Q: Spring Rebound. A 1.00 kg object slides across a rough horizontal surface. The coefficient of…

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Q: The block remains on the track at all times. (b) Calculate d. _____

A: We can use the relation Work done by non conservative force = change in total energy. m = 0.70 kg k…

Q: A system contains an ideal horizontal spring, with an un-stretched length of 8 N/cm. Calculate the…

A: Write the given values with the suitable variables. x1=29 cm=0.29 mx2=32 cm=0.32 mk=8 N/cm=800 N/m…

Q: A 40.0° 1.50 m B 1.00 m C k = 900 N/m mm hh

A: Mass of block (m) = 2.50 kgBlock starts from rest at point A at the top of a 1.50 m long…

Q: A block of mass 2.0 kg is attached to a horizontal spring that has a force constant of 2.40 x 103…

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Q: = 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a…

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Q: A block of 3.00kg mass is placed against the horizontal spring of constant k = 875 N/m and pushed…

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Q: A block of mass 3.60 kg is placed against a horizontal spring of constant k = 825 N/m and pushed so…

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Q: A 10,000-lb airplane is launched from a catapult. The spring of the catapult (ks = 150 lb/in) is…

A: Solution: Given: 1 ft = 12 in m = mass of airplane = 10000 lb k = spring constant of catapult = 150…

Q: A block of mass 3.20 kg is placed against a horizontal spring of constant k = 865 N/m and pushed so…

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Q: A bungee jumper with a mass of 77.5 kg is standing on a platform 65.1 m above a lake. The length of…

A: Give: m = 77.5kg h0 = 65.1m L0 = 15.3m K = 155N/m h1 = 47.7m V1 = ?

Q: A block of mass 4.2 kg is placed against a horizontal spring of constant of 939 N/m and pushed so…

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Q: spring laying HORIZONTALLY on a flat surface is compressed 4.5 cm (convert to m), and a ball is…

A: Given:-  A spring laying in the horizontal.  Displacement of the compressed spring x = 4.5 cm =…

Q: A block of mass 2.60kg is placed against a horizontal spring of constant k = 795 N/m and pushed so…

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Q: Below is a conservation of energy problem. The solution to this problem is provided. Assess whether…

A: The solution is definitely not correct .Also the Question is itself incorrect at last line where it…

Q: A block of mass 3.20 kg is placed against a horizontal spring of constant k = 835 N/m and pushed so…

A: solution as

Q: A 6.00 x 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.500 m by a large…

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Q: Problem 7: A block of mass 5.5 kg is sitting on a frictionless ramp with a spring at the bottom that…

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Q: The elastic energy stored in your tendons can contribute up to 35% of your energy needs when…

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Q: h four fewer passengers than before) is 1600 kg, what should the spring constant be for a maximum…

A: We know that the mass of the elevator is 2000 kg and broken cables is falling at the speed of 8 m/s…

Q: A block of mass 2.60 kg is placed against a horizontal spring of constant k = 815 N/m and pushed so…

A: Given values -  Mass = m = 2.6 kg  Spring constant = k = 815 N/m Compression = x = 0.06 m

Q: m. The car then ramp which is frictionless except for the 2.5 meter patch shown. Next the car goes…

A: Use law of conservation of energy  MEi=MEf  Initially the car has only spring potential energy= Us…

Q: A pogo stick has a spring with a force constant of 2.50 x 104 N/m, which can be compressed 12.4 cm.…

A: Given data : Force constant of spring,    k = 2.50 x 104 N/mSpring compressed, x = 12.4 cm = 0.124…

Q: A block of mass 2.40 kg is placed against a horizontal spring of constant k = 795 N/h and pushed so…

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Q: The mass slides across a rough patch of length 0.57 m where the coefficient of kinetic friction is…

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Q: A 12 kg block is released from point A as shown in the figure.  Its path from A to the spring is…

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Q: A spring with a spring constant 2.40 N/m attached to a block and the block is initially at rest with…

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: A 5 x 105 kg subway train is brought to a stop from a speed of 0.420 m/s in 0.380 m by a large…

A: Given data: Mass of train is, m=5×105 kg. Initial speed of train is, u=0.420 m/s. Final speed of…

Q: A system contains an ideal horizontal spring, with an un-stretched length of 29 cm and a spring…

A: The work done to stretch the spring is equal to elastic potential energy, which is dependent on the…

Q: Problem 10: A pogo stick has a spring with a force constant of 2.50 x 104 N/m, which can be…

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Q: A pogo stick has a spring with a force constant of 2.50×104 N/m, which can be compressed 12.0 cm. To…

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Q: The elastic energy stored in your tendons can contribute up to 35% of your energy needs when…

A: Spring constant of tendon: k= 33 N/mm=  N/m= 33000 N/mDuring sprint: stretch in tenon: = 45 mm=…

Q: A block of mass 3.20 kg is placed against a horizontal spring of constant k = 715 N/m and pushed so…

A: We need to calculate the elastic potential energy of the spring. Also, the speed of the block after…

Q: A pretty box from taylor swift batumbakal with a mass of 20.0 Kg is moving at a speed of u = 8 m/s.…

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Q: Find the potential energy of a spring that has been stretched by a 10.0 N force, displaced from the…

A: Potential Energy of spring is given  by k=-Fx U=12k∆x2 Given : Force F = 10 N x1=0x2=10 cm =0.1 m…

Q: By what factor does Tom need to increase the spring constant to hit his potential energy goal?

A: elastic potential energy stored in a spring of spring constant k when stretched a distance x is…

Q: A pretty box from taylor swift batumbakal with a mass of 20.0 Kg is moving at a speed of u = 8 m/s.…

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Q: In the figure, a 2.6 kg block is accelerated from rest by a compressed spring of spring constant 660…

A: Given: In this question, the given details are In the given figure, A 2.6 kg block is accelerated…

Q: A block of mass 2.00 kg is placed against a horizontal spring of constant k = 765 N/m and pushed so…

A: Solution: Given: m = mass of block 2.00 kg   k = force constant of spring = 765 N/m s = compression…

Q: A horizontal spring on a frictionless surface with a spring constant of 40 N/m is compressed 0.3 m…

A: Given x=0.3m K=40N/m Mass= 2kg Stored energy in spring, U=12kx2

Q: A spring with constant k=200 N/m is fixed to the top of an incline that makes an angle of 40.0…

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Q: A box of mass 2.0 kg, traveling horizontally, hits an uncompressed spring with an initial velocity,…

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Q: You have been hired to design a spring-launched roller coaster that will carry two passengers per…

A: So we have given a spring-launched roller coasterCar goes up to 10 m high then down to lowest point…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.