A 30.0° frictionless inclined plane has a spring at the bottom. A block of mass \( m = 5.00 \, \text{kg} \) starts from rest at the top and comes to rest momentarily at the bottom when it compresses the spring by \( x = 0.20 \, \text{m} \). The total distance the block travels along the incline is \( (d + x) \), where \( d = 1.00 \, \text{m} \) and \( x = 0.200 \, \text{m} \). Determine the spring constant \( k \). (Consider conservation of energy 'system')**Diagram Explanation:**- The diagram shows an inclined plane at an angle \( \theta = 30.0^\circ \).- A block of mass \( m \) is positioned at the top of the incline, with a velocity vector \( \vec{v} \) indicating its initial motion downwards.- The incline has a spring at the bottom, which compresses when the block travels down.- The spring is labeled with a spring constant \( k \).**Answer Options:**- 2,740 N/m- 1,470 N/m- 996 N/m- 3,950 N/m- 1,080 N/m

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