By what factor does Tom need to increase the spring constant to hit his potential energy goal?
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Tom has built a large slingshot, but it is not working quite right. He thinks he can model the slingshot like an ideal spring with a spring constant of 55.0 N/m. When he pulls the slingshot back 0.445 m from a nonstretched position, it just does not launch its payload as far as he wants. His physics professor "helps" by telling him to aim for an elastic potential energy of 19.5 J.Tom decides he just needs elastic bands with a higher spring constant. By what factor does Tom need to increase the spring constant to hit his potential energy goal?
Factor of Spring constant Increase:
During a follow‑up conversation, Tom's physics professor suggests that he should leave the slingshot alone and try pulling the slingshot back further without changing the spring constant. How many times further than before must Tom pull the slingshot back to hit the potential energy goal with the original spring constant?
factor of pullback distance increase:
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- Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. = 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk = 0.16. The final velocity of the block is 9.78 m/s. How much is the second spring compressed by when the block comes to a stop against it? Simplifies to X₁ = 0.40 m h₁ = 0 m Vi = 0 m/s xf Wnc = 0 J 2 Wnc + mgh₁ +1/2 kx₁² +½ mv² = mgh₁+½ kxf² +½ mvf2 = k₁ = 2750 N/m k₂= 350 N/m m = 4.6 kg 2 ½ k₁x₁² = mghf + ½ K₂Xf2 2 ½ k₁x;² — mghƒ _½ k₂xf² Xf= 2750 N/m 350 N/m (0.4 m)2 x k 2 2gh -X f= X₁ = ? m h₁ = 2.8 m Vi = 0 m/s 0.141 m 2(9.8…The Slingshot is a ride for two people. It consists of a single passenger cage, two towers, and two elastic bands. Potential energy is stored in the elastic bands and the passenger cage is released. On the way up, this potential energy in the elastic bands is converted into the kinetic energy of the cage. At the maximum height of the ride, the energy has been converted into gravitational potential energy of the cage. The slingshot has two towers of height h = 71 m. The towers are a distance d = 31 m apart. Each elastic band has an unstretched length of L0 = 42 m and a spring constant of k = 295 N/m. The total mass of the passengers and cage is m = 395 kg. The car is pulled down to the ground in the middle of the two towers.Tom has built a large slingshot, but it is not working quite right. He thinks he can model the slingshot like an ideal spring with a spring constant of 35.0 N/m. When he pulls the slingshot back 0.375 m from a nonstretched position, it just does not launch its payload as far as he wants. His physics professor "helps" by telling him to aim for an elastic potential energy of 17.0 J. Tom decides he just needs elastic bands with a higher spring constant. By what factor does Tom need to increase the spring constant to hit his potential energy goal? factor of spring constant increase: During a follow-up conversation, Tom's physics professor suggests that he should leave the slingshot alone and try pulling the slingshot back further without changing the spring constant. How many times further than before must Tom pull the slingshot back to hit the potential energy goal with the original spring constant? factor of pullback distance increase: In which of the two scenarios does Tom have to pull…
- A 1.30 kg block slides on a frictionless horizontal surface until it encounters a spring with a force constant of 520 N/m. The block comes to rest after compressing the spring by the distance of 2.50 cm.What was the initial speed of the block ? O 0.25 m/s 5.0 m/s O 31.6 m/s O 0.50 m/sThe class I'm taking is physics for scientists and engineers! I am completely stuck. Need help. I have attached the problem. Please view both attachments before answering. If you can please explain your answer so I can fully understand. Thank you!A 250 g block on a 30° ramp with μk = 0.17 is pushed against a spring. The constant of the spring is 1400 N/m and the spring is compressed 13.0 cm. After being released, the block will travel 3.4 m up the ramp (that includes the 12 cm) before shooting off the end. How fast will the block be going when it shoots off the edge of the ramp?
- A .500kg block attached to a spring with length .60m and force constant 40.0 N/m, is at rest with the back of the block at point A on a frictionless horizontal air table. The mass of the spring is negligible. You move the block to the right along the surface by pulling with a constant 20.0 N horizontal force. what's the block's speed when the black of the block reaches point B, which is 0.25 m to the right of point A.Hello, can you solve the first 3 parts? Thank you!A 7.0 kg block on a horizontal, frictionless surface is attached to a light spring (force constant = 1.2 kN/m). The block is initially at rest at its equilibrium position when a force of magnitude P acting parallel to the surface is applied to the block, as shown. When the block is 8.0 cm from the equilibrium position, it has a speed of 0.80 m/s. How much work is done on the block by the force P as the block moves the 8.0 cm? A. 7.4 J B. 5.4J C. 6.1J D. 6.7J E. 4.9J
- A child’s toy consists of a m = 33 g monkey suspended from a spring of negligible mass and spring constant k. When the toy monkey is first hung on the spring and the system reaches equilibrium, the spring has stretched a distance of x = 11.4 cm, as shown in the diagram. This toy is so adorable you pull the monkey down an additional d = 6.7 cm from equilibrium and release it from rest, and smile with delight as it bounces playfully up and down. a) Calculate the speed of the monkey, ve, in meters per second, as it passes through equilibrium.A 10.0 kg block is released from point A in the figure. The track is frictionless except for the portion BC, of length 14 m. 10.0 kg 3.00 m B C k mmmmmm plz help and use g = 9.8 The block travels down the track, hits a spring of force constant k = 1,631 N/m, and compresses it 0.1 m from its equilibrium position as it comes to rest momentarily. Determine the coefficient of kinetic friction between surface BC and the block. Express your answer to at least two digits after the decimal point.Please answer and solve the question correctly. Thank you!