A 7.0 Kg of glass bowl (Class= 840 J/Kg C°) contains 16.0 Kg of punch at 25.0°C. 2.5 Kg of ice (Cice= 2.0 x 10° J/Kg C°) are added to the punch. The ice has an initial temperature of -20.0°C, having been kept in a very cold freezer. The punch mat be treated as if were water (Cwater = 4184 J/Kg C°), and it may be assumed that there is no heat flow between the punch ball and the external environment. What is the temperature of the punch, ice and bowl when they reach thermal equilibrium? Draw the illustration.
A 7.0 Kg of glass bowl (Class= 840 J/Kg C°) contains 16.0 Kg of punch at 25.0°C. 2.5 Kg of ice (Cice= 2.0 x 10° J/Kg C°) are added to the punch. The ice has an initial temperature of -20.0°C, having been kept in a very cold freezer. The punch mat be treated as if were water (Cwater = 4184 J/Kg C°), and it may be assumed that there is no heat flow between the punch ball and the external environment. What is the temperature of the punch, ice and bowl when they reach thermal equilibrium? Draw the illustration.
Related questions
Question
Transcribed Image Text:1. A7.0 Kg of glass bowl (clas= 840 J/Kg C°) contains 16.0 Kg of punch at 25.0°C. 2.5 Kg of ice
(Ciee= 2.0 x 10° J/Kg C°) are added to the punch. The ice has an initial temperature of -20.0°C,
having been kept in a very cold freezer. The punch mat be treated as if were water (cwater =
4184 J/Kg C°), and it may be assumed that there is no heat flow between the punch ball and
the external environment. What is the temperature of the punch, ice and bowl when they
reach thermal equilibrium? Draw the illustration.
2. 50.0 g of ice at 0°C is added to 200.0 g of water at 40.0°C contained in a 100.0 g copper
calorimeter. If the final temperature of the mixture is 16.0°C, find the heat of fusion of ice in
cal/g. Draw the illustration.
3. An ice chest at a beach party contains 24 cans of soda at 4.0°C. Each can has a mass of 0.35
Kg and specific heat capacity of 3800 J/KgC°. Someone adds a 5.0 Kg watermelon at 29.0°C
to the ice chest. The specific heat capacity of watermelon is nearly the same as that of
water. Ignore the Cice chest, Determine the final temperature of the soda and watermelon.
Draw the illustration.
4. How much heat energy in calorie is necessary to convert 100.0 g of ice at 0°C to water vapor
(steam) at 105 °c? Draw the illustration.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
